<p>An integer from 100 through 999, inclusive, is to be
chosen at random. What is the probability that the
number chosen will have 0 as at least 1 digit?</p>
<p>I didnt understand this that well either, but i googled it and a result came up. the explanation helps: There are 9 possible digits that can be in the hundreds’ place, tens’ place, and the ones’ place (1-9). Thus, there are 9^3 = 729 numbers between 100 and 999 that do NOT have 0 as any digit. Since there are 900 integers between 100 and 999 inclusive, there are 900 - 729 = 171 integers between 100 and 999 inclusive that have AT LEAST 0 zero as a digit.</p>
<p>Therefore, the required probability is 171/900</p>
<p>How can you have a zero in the hundreds place. I thought it had to be between 100 and 999.</p>
<p>Ah I see herozero. That’s a good method haha I’ll remember that</p>
<p>On these I always just manually write out all the possible numbers and eliminate answers, then use common sense estimation to whittle down the remaining answers =/. The other guy’s method seems way too complex to be useful in a high pressure test situation.</p>
<p>@puremeerkat You can’t. As herozero said, there are only nine choices (1-9).</p>