<p>The surface of a 3dimensional solid consists of faces each which has the shape of polygon.what is the least number of such solid can have?
a.2
b.3
c.4
d.5
e.6
please explain the problem</p>
<p>This doesnt look like an SAT problem.If it is from the College board book or online course i will draw a diagram and explain it but if it is not,dont waste your time.</p>
<p>lol this problem is from the psat test sat 05 test of cb (sec 2 question no.17).</p>
<p>Answer: 4
If there were 3 faces of the shape, then the shapes would not be able to connect to make something 3D. However, if there are 4 faces of a shape, you can connect all 4 to create a 3D solid, a tetrahedron. Sorry if this explanation is a bit confusing, just look at a picture of a tetrahedron and you should understand: <a href="http://www.coolmath.com/reference/images/polyhedra-tetrahedron.gif%5B/url%5D">http://www.coolmath.com/reference/images/polyhedra-tetrahedron.gif</a></p>
<p>A tetrahedron actually has 4 faces. The answer is C. the_pakalypse's explanation, however, is still correct if you replace all 2's with 3's and all 3's with 4's.</p>
<p>^^ oops
silly mistake.. explains my SAT math scores =/ lmao</p>
<p>thanks DUDE</p>