<p>plz tell me the answer you get when you work this out</p>
<p>f(x) = Squareroot(x^2+1)</p>
<p>find the slope of the secant line to f (x)</p>
<p>Secant line: A line which passes through at least two points of a curve. Unless you specify which two points you are talking about, it can be anything.</p>
<p>no just the slope equation or wutever of the secant line</p>
<p>like working out that whole f(x+h)-f(x) / h</p>
<p>Secant line slope equation is the same as just a slope equation with two points. f(b) - f(a) / (b-a). Are you sure you don't mean the tangent line? Because you seem to be describing derivative stuff.</p>
<p>yeah that equals the same thing, what the teacher said in calc. no i don't mean the tangent. grr better yet</p>
<p>plz simplify (squareroot((x+h)^2 +1) - squareroot(x^2+1))/ h</p>
<p>make it so that there if no h term in the bottom or if h was replaced with 0, there is still a term with x terms</p>
<p>Is that a limit? Because, that equation looks like the definition of the derivitive of sqrt(x^2 + 1), which would be x/sqrt(x^2+1)</p>
<p>i don't know this is my 1st week of calculus, i have a foreign teacher and can't read half the stuff he writes on the board im really overwhelmed. The 1st thing says to find is the slope of the secant line to f(x)</p>
<p>Multiply the numerator and the denominator by sqrt((x+h)^2+1) + sqrt(x^2+1). It'll come out to be (2x+h) / (sqrt((x+h)^2+1) + sqrt(x^2+1)). When you put h=0, it'll be x / sqrt(x^2+1). Of course, you could have done it with simple derivative method.</p>
<p>well hes foreign, so i learn nothing</p>