Math Q in Blue book

Test Preparation
1

<p>pg. 476 #18 in blue book. Please help and explain!</p>

2

<p>Actually, the first and easiest thig to do would be to go to the top IMPORTANT thread "Consolidated List of Solutions ...". The andswer is right there.</p>

<p>Three additional ones:</p>

<p><a href="http://talk.collegeconfidential.com/showthread.php?t=85346&highlight=cards+arrangements%5B/url%5D"&gt;http://talk.collegeconfidential.com/showthread.php?t=85346&highlight=cards+arrangements&lt;/a&gt;&lt;/p>

<p><a href="http://talk.collegeconfidential.com/showthread.php?t=93147&highlight=cards+arrangements%5B/url%5D"&gt;http://talk.collegeconfidential.com/showthread.php?t=93147&highlight=cards+arrangements&lt;/a&gt;&lt;/p>

<p><a href="http://talk.collegeconfidential.com/showthread.php?t=68614&highlight=cards+arrangements%5B/url%5D"&gt;http://talk.collegeconfidential.com/showthread.php?t=68614&highlight=cards+arrangements&lt;/a&gt;&lt;/p>

3

<p>THankyou!</p>

<p>There are other explainations, but this is the only one on the first link that makes sense to me.</p>

<p>Here is a straight foward explanation; This is a simple permutation problem...</p>

<p>5 cards arranged in random order (no repetition):
5! = 5<em>4</em>3<em>2</em>1 = 120 total combinations</p>

<p>Subtract the number of combinations possible with C at the end.
That value = 4! because C is fixed and there are 4 cards left to be arranged in random order.</p>

<p>4<em>3</em>2<em>1 = 24
Multiply this by 2 to account for the other end,
24</em>2 = 48
120 total - 48 with C at the end
120 - 48 = 72</p>