<p>@ southeasttitan</p>
<p>points were given to you. m = slope = (y2-y1)/(x2-x1). Chose any of two out of three given. For example, using (20, 16) and (8,8) you get (16-8)/(20-8) = 8/12 = 2/3.</p>
<p>3x=2y is right.</p>
<p>the polygon one, with ten sides, and each side less than 1 meter, and if the perimeter must be 10, what is the least number of sides? it's 11, right? b/c if each side is even.9999999999999999999999999, you still need 11.?</p>
<p>^ Exactly.</p>
<p>oh...i got that one of the sides had to be 14, but i ran out of time, so i guessed i think the next number higher than 28...</p>
<p>yes, i think i got 5/44, because if you started multiplying out the first few terms of the sequence, you'd see that if you multiplied them, you could cancel out every diagonal numerator with denominator...basically you were left with the numerator of the first term and denominator of the last term....unless of course i'm speaking about a totally different question, in which case disregard my explanation. haha. short term memory loss.</p>
<p>0 > x > 2 > y</p>
<p>(y-x)/(xy) > 0</p>
<p>this is the only one that made sense, because from what they give you, you can deduce that x and y are positive, and y MUST be larger than x, so if you subtract x from y, you will get a positive number over the positive denominator (the product of x and y will be +)</p>
<p>I think I have -3 in math</p>
<br>
<p>< Looks like October will bring a retake.. Anyway, concerning the book question, I'm pretty sure about x-t+s. x was definitely the new number of the books. A variable for the original collection wasn't designated.</p>
<br>
<p>it /is/ x-t+s
i plugged in numbers to check; it was correct.</p>
<p>hey desigirl how can 0 be greater than x if x is greater than 2??</p>
<p>For the balloon one, I just wrote all the possible combos down where they could still have 10 balloons.</p>
<p>I think it was 3,3,3,1; 2,3,3,2; 3,2,3,2; and 3,3,2,2--four different combos. Anything else would have been less or more than 10 balloons.</p>
<p>For the picking the number for the box question, were their directions that it had to go from greatest to least or something? because your all saying 745745 or w.e, could it have been 475475, or even a different # like 835835? What exactly were the restrictions on that question?</p>
<p>It obviously couldn't have been the last one; they gave you a 7 in one of the boxes. The point of the question was that, no matter which other two numbers you chose to add to seven to total sixteen, the seven would have to repeat in the specified box.
So yes, you could have used a different series of numbers, but your answer would have been the same.</p>
<p>ooo stupid question on my part. i felt like it was an easy question when i did it im just not sure if i put 7 or not. i better have. if i omitt 1 and get 2 wrong what do u think im looking at for a scaled score?</p>
<p>at least a 730.</p>
<p>I'm really annoyed at all the stupid mistakes I made. I knew how to do all of them, but I think i have like 4 or 5 wrong due to absolutely retarded mistakes. Looks like I'm going to have to retake again because I got 4 wrong last time i took it. Hopefully the curve is nice. What do you guys think a -5 (raw points) is like on this curve? For the dec, -5 raw was a 710.</p>
<p>not at least a 730... i believe at least a 720 though</p>
<p>I got 2 wrong and 1 grid in which is the same as 1 omit and 2 wrong and got a 720 in March</p>
<p>I think you will do even higher tomackze...this test was more difficult imo then the May test date and most of the practice tests I took. Three problems on factorials, permutations, and sequences = pretty unusual. Albeit the two sequence problems were not bad, the majority of students freeze up when they see sequences or series. However, both the permutations and factorial problems seemed exceedingly strange for the SAT reasoning test.</p>
<p>I posted a topic in this forum 1-2 days before the test about "quirky/oddball math problems" and people really didn't even take my concern seriously about sequences, perms/combs, etc. showing up on the reasoning test.</p>
<p>So, the point is we damn well better have a more forgiving curve than the standard curve for the reasoning test.</p>
<p>What about the question about the mixtures and fractions was the answer something like 22.5?? </p>
<p>and what about the question that asked about a slope of a line that was tangential to a circle on a x, y plot?</p>
<p>ok everyone for the parabola problem, it was an incorrectly written problem. the problem did not specify whether or not the shaded region was inclusive or exclusive of the borders. If it was inclusive, then the correct answer was none. If it was exclusive, then the correct answer was y>x^2 and abs(x)<2.</p>
<p>I've emailed collegeboard about this but if more people do it its more likely to get their attention so they'll drop it so everyone email them about this problem and its ambiguity!</p>
<p>i agree that the problem was ambiguous oryZa, and i will email collegeboard now.</p>