<p>The label on a cylindrical can extends from the top to the bottom of the can. One edge of the label overlaps the other by 1 centimeter.If the can is 10 centimeters tall and the diameter of the base is 8 centimeters, what is the perimeter, in centimeters, of the label?</p>
<p>A) 10 + 8π
B) 11 + 8π
C) 20 + 16π
D) 20 + 18π
E) 22 + 16π</p>
<p>@mshQwdy
If I understood the question correctly, I think that the answer if E)22 + 16pi.</p>
<p>Perimeter = 2<em>Side1 + 2</em>Side2 = 2( 10 ) + 2( 2<em>pi</em>4 + 1 ) = 20 + 2( 8<em>pi +1 ) = 20 +16</em>pi + 2 = 22 + 16*pi</p>
<p>Would that be correct?</p>
<p>^ I got the same thing. </p>
<p>OP, try to imagine unwrapping the label from the can: it’s a rectangle. </p>
<p>You’re already given two of the sides/lengths (10 inches is the height, so both lengths together would be the 20). Add 2 centimeters as there is a 1 centimeter overlap for each side of the label.</p>
<p>Since the label wraps around the can, you can find the widths by finding the circumference of the can with 2πr. The radius is 4 so the circumference is 8π, which is one of the widths. 16π is both of the widths added up.</p>
<p>—> 22 + 16π</p>
<p>yes right 
Thank you </p>