<ol>
<li>x-2y>13
y+x<13</li>
</ol>
<p>Which of the following ordered pairs (x,y) is a solution of both of the inequalities above?</p>
<p>a. (3,-1)
b. (12,3)
c. (8,3)
d. (10,2)
e. (1,5)</p>
<p>My book says that D is correct. Now, I understand how D fits into the second inequality, but I don't understand how it fits into the first inequality. Doesn't 10-4=6?</p>
<p>My second question is, how can I easily solve inverse proportion problems? Is there a trick to doing these? I always get confused when doing these.</p>
<p>Thanks :)</p>
<p>I don’t know about the problem but I could help with you inverse proportion.</p>
<p>If a varies inversely to b, and a = x when b = y, what does b equal when a = 5?</p>
<p>To do these, first you have to setup the equation which is b = k * 1/a or a = k * 1/b where k is a constant.</p>
<p>Then you plug in the numbers, y = k * 1/x From here, you solve for k.</p>
<p>Then it’s as simple as </p>
<p>b = k * 1/5 Here, you should already know what k equals and just have to multiply.</p>
<p>Hope that helped :)</p>
<p>Are you sure it isn’t (10, -2)?</p>
<p>Thanks. And yea, I’m pretty sure it isn’t (10,-2). Maybe the company made that typo when it published the book.</p>