Math Sat Iic Tough Question

<p>Its prob. not tough for most of you, but can u explain how to get the answer for this?</p>

<p>The area bound by the relation |x| + |y| = 2 is
a) 8
b) 1
c) 2
d) 4
e) there is no finite area</p>

<p>I was thinkin bout graphing it in calculator, but then i realized idont know how to put this type of equation in. The answer is a.</p>

<p>actually you can use a graphing calc... that's what i did.</p>

<p>I plugged in 2 equations</p>

<p>y = 2 - |x|</p>

<p>and </p>

<p>y = -(2-|x|)</p>

<p>(that's possible by def of abs value)</p>

<p>You get an area bounded around the origin. It's made up of 4 triangles each with bases and heights of 2. 1/2(2)(2)=2. 2*4 triangles = 8.</p>

<p>does that make sense?</p>

<p>You can rewrite the relation as y= +/-( 2 - |x|) </p>

<p>So I think there isn't a finite area. </p>

<p>I am not sure though. This is just a guess.</p>

<p>Woah, nifty.</p>

<p>I. For y>=0
y = 2 - |x| (that means 0<=y<=2)
A fragment of the graph y = -|x| + 2 above and on the x-axis (-2<=x<=2).</p>

<p>II. For y<0
y = |x| - 2 below x-axis (-2<x<2, -2<=y<0).</p>

<p>Son of Liberty -
you got the area right, but you took a liberty of not limiting neither x nor y, so you got two unlimited graphs

They don't bound an area.</p>

<p>There would be a finite area if we were given
y<=-|x|+2 AND y>=|x|-2.</p>