<p>Can anyone help me on on question 10 (section 2) from the the SAT Preperation Booklet (2008-2009)? I know it's probably really easy, and I read the description on collegeboard, but for some reason I still don't understand it. </p>
<p>What is the greatest possible area of a triangle with one side of length 7 and another side of length 10?</p>
<p>(a) 17
(b) 34
(c) 35
(d) 70
(e) 140</p>
<p>Thanks</p>
<p>it's c)35 ...........</p>
<p>She has the answer key gluttony.
If you were careless then you probably picked D. 70. </p>
<p>7 x 10 = 70. </p>
<p>Area of a triangle is 1/2BH</p>
<p>70/2 = 35. </p>
<p>Keep in mind that 7 and 10 must be the longest sides. If you pick 16 as the other side, 7 and 10 would still be the legs. pick a smaller number and .. well, that wouldn't make any sense.</p>
<p>ooops........sorry</p>
<p>an interesting key fact to know is that using 2 sides to make a right triangle makes the largest area.</p>