<p>1.If all the terms of a geometric series are positive,the first term of the series is 2,and the third term is 8,how many digits are there in the 40th term?
A 10
B 11
C 20
D 13
E 14
key and explanation?
2.Which of the following lists all and only the vertical asymptotes of the graph y=x/(x<em>x-2</em>2)
A.x=2 only
B.y=2 only
C.x=2 and x=-2
D.y=2 and y=-2
E.x=2 x=-2 x=0
key and explanation?</p>
<p>I will apreciate your answers :)</p>
<ol>
<li><p>A geometric series is multiplied by the same constant every time
2<em>n</em>n=8
n=2
2*2^(n-1) is the formula for the series
2^40 has 13 digits.</p></li>
<li><p>Vertical asymptotes occur when the denominator equals zero. Plugging in
x=0 results in a denominator of 4. Rule out E.
X=2 is an asymptote, obviously, as 2<em>2-2</em>2 equals zero.
Rule out B and D.
-2<em>-2= 2</em>2 so X=-2 is also an asymptote. C is the correct answer.
The function can be written much more simply as y=x/(X+2)(X-2)</p></li>
</ol>
<p>the first one i think jbruner explained well.</p>
<p>the second one...</p>
<p>lets see here.</p>
<p>x/(x<em>(x-2)</em>2)</p>
<p>plugging in 0 will result in zero in denominator right? or did i misinterpret the problem? cause 0<em>(0-2)</em>2 is zero. </p>
<p>or is the problem actually saying, </p>
<p>x/(x<em>x - 2</em>2) <- without the parenthesis in the middle</p>
<p>Clarification would help here. personally i think the answer is E.</p>
<p>I would assume its E and ur former assumption would be correct. But it depends on how the problem is written and we'd neeed to c that in order to answer it correctly. I just dont think they would put 2*2 in the denominator as its own term. But jbruner answered it correctly as to how u wrote the problem originally .</p>
<p>you probably did kaplan's because i just did that first question 15mins ago
=)</p>