MAY 2010 Physics

<p>I only put bend mirror because no matter how far back you move it to create parallel lines coming out you need parallel lines going in, so moving it further back would never create parallel rays going in… but I might be wrong. maybe I didn’t fully understand the question…</p>

<p>What did you guys say for the one with the air resistance equaling g?</p>

<p>and</p>

<p>The one with the scale and the two weights of 10 N? Was the reading 10 or 20?</p>

<p>I put constant velocity, since if Air resistance going up is equal to G going down, the net force is zero. So acceleration is zero</p>

<p>not sure about the other one, but I put 10</p>

<p>Anyone’s 2nd or 3rd time taking it? How would you describe this test’s difficulty relative to your previous ones? </p>

<p>My first time taking it, and let me say, it was hard.</p>

<p>Did I misread the mirror problem incorrectly?</p>

<p>The the third choice state to bend the mirror to make it have a larger radius of curvature or smaller radius?</p>

<p>For the two masses passing through a pulley w/ force measurer, I put 0…</p>

<p>misterkevinsun, the answer was about making the radius smaller.</p>

<p>Typical Asian, was your reasoning that the tension had to be the same for both blocks?</p>

<p>I sped through that question, so I thought the system was in equilibrium and that tension of both strings is 10, but now that I think about it. If thats true, then there is a tension of 10 N pulling to the left of the scale too. So it could add up to be 20.</p>

<p>the answer to the spring scale problem is 10 because of Newton’s 3rd law: every force has an equal and opposite reaction force. I’m not sure exactly how to explain this but I saw the exact same problem before only with weights of 5, and the answer was 5N.</p>

<p>Wait if its 1 force measurer and the same tension on either side, wouldn’t it be canceled out?</p>

<p>the spring scale is 10n.
what’s the general consensus about this test? I say it’s a little harder than most of the practice tests i took on PR, so i’m expecting a raw score >56 to be 800. What do you guys think?</p>

<p>I took Kaplan and Barrons tests… Barrons was actually easier than the actual, despite being more engineering focused. The Kaplan tests were so much easier than either. I thought the actual test was frickin hard. At “20 min left” I had about 30 questions to go through -.-</p>

<p>How bout the one where you had to show the diagrams for light refraction? which was the normal line?</p>

<p>I put B. Or the second one in the first row. I was debating between that and A, but rushed through it and put B.</p>

<p>All I took was the sparknotes one, and I think that this was a little easier. But… I skipped Physics B and jumped straight into C so I have very little knowledge on waves, optics, and thermo stuff. Had to cram it all within the past week It was good that there was a lot less on the qualitative aspects of those. </p>

<p>Oh, what was the best half life for measuring the mummy that was 5000 years old? I put 5000 as the half life.</p>

<p>For my reasoning behind the 10 N question:</p>

<p>Imagine that one side of the spring was connected to a wall. The scale would read 10 N by design. In this scenario, the tension in the string attached to the 10 N block is 10 N ( to counteract gravity). Since tensions of a the same string are equal, the force on the spring by that string is 10 N also. Since the spring doesn’t move, there is no net force on the spring, and the string attached to the wall has a tension of 10 N on both ends.</p>

<p>Replacing the wall with a 10 N block creates identical tensions in the string, causing the scale to display the same force it did in that scenario, 10 N.</p>

<p>Yeah I put 5 x 10^3 too TA.</p>

<p>faunts, great explanation. for the half life of the mummy i put 5 years even though I had no idea… I just didn’t think any of the other answers made any sense.</p>

<p>Faunts, I sort of understand your explanation, but since the tensions are on opp. directions of the force gauge, and like you said, there is no net force, wouldn’t it be 0? o.O</p>