<p>My 12 year old was able to solve the blue book math problem page 657 #18, however, she would like to find a simpler solution than what was posted on CC.</p>
<p>She did not understand the equations that were in the consolidated blue book CC explanation.</p>
<p>At time t=0, a ball was thrown upward from an initial height of 6 feet. Until the ball hit the ground, its height, in feet, after t seconds was given by the function h above, in which c and d are positive constants. If the ball reached its maximum height of 106 feet at time t=2.5, what was the height, in feet, of the ball at time t=1?</p>
<p>My 12 year old is a member of Johns Hopkins Center for Talented Youth. When you enter 7th grade, JHU requires that to stay in CTY, you must take the SAT. JHU included a sample real SAT test with her application materials. She scored 690 math. If she scores 700, she can get into a higher gifted program. When she scored the 690, I emailed an SAT tutor to see if he had any tips for her to break 700. He told me to buy the Blue book and just work on real SAT problems a few days before the March test. That is why she is taking the SAT.</p>
<p>Ryanone, first of all congratulations to your daughter for taking the initiative to push herself forward and strengthen her education. Not many 12-year-olds are like that :)</p>
<p>When I look at the problem, this is how I think to solve it:</p>
<p>We know h=106 when t=2.5 and h=6 when t=0. We can set up a system:
106=c-(d-4(2.5))^2
6=c-(d-4(0))^2</p>
<p>Solve for c & d, then plug them in along with t=1. Very similar to xiggi's.</p>
<p>There may or may not be an easier way to do it but this one gets the right answer.</p>
<p>Ryanone, I assure you that you will never encounter a question as hard as this on any SAT test. </p>
<p>Outside this question, I have never seen any other question where you are required to manipulate parabolic equations. (I've done almost 25 full practice tests from CB including old SAT tests dating back to as far as 1999.)</p>
<p>So you don't need to worry.
One more thing, I would like to recommend you to mystery tutor.</p>
<p>If all you need is to break 700, he can show you a lot of trick (techniques actually) that work. the best part is that it's free. :P</p>
<p>i always take heat for only needing 1800 to get into some ivys (according to some of the coaches, obviously not harvard or yale), but wow if i started when i was 12 i think id be at like 2300 by now... i didnt no what an sat was till this fall (canada)</p>
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wow if i started when i was 12 i think id be at like 2300 by now... i didnt no what an sat was till this fall (canada)
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<p>Not true. A lot of the asian kids that I know have been studying since they were 10 and they're not even CLOSE to a 2300. </p>
<p>It's not about time spent; preparation only makes it such that you perform your best. Most people just don't have the talent to get a 2300+. Now, I'm not saying you don't, but starting at age 12 makes little difference.</p>
<p>@anhtimmy: you may be right in that you are not expected to manipulate parabolic equations, but I don't think that was the approach that CB was looking for, which I think is the following:</p>
<p>h(t) = c - (d-4t)^2</p>
<p>Since c > 0, and something squared is always positive, h is biggest when the number inside the parentheses is 0.</p>
<p>Thus, maximum h is when d = 4t. The problem gives max height of 106 at t=2.5, so d = 4*2.5 = 10, and c = 106.</p>
<p>The whole point of taking the SAT at 12 is to see how a gifted child performs on an above-grade test without prep. Extensive prepping for it skews the result.</p>
<p>And that "higher gifted program" the OP mentioned (now a couple of years ago) is probably SET, which isn't really an additional program at all. It's a long-term study that kids who score extremely well (over 700 before age 13) on CR or M are invited to participate in. There's a magazine and a website, too, but it's not as though there are special camps that only SET kids can go to or anything. Oh, and there is a nice ceremony and a free lunch at JHU, too, at which kids get a nice medal.</p>