Not sure about simple AP Calculus problem...

<p>Graph the following function</p>

<p>f(x)= </p>

<p>1+abs(3-x) if x is not equal to 3
2 if x =3</p>

<p>I am unsure about how this graph should look. Will the "v" shaped graph be cut off near the bottom because of f(x)=2? Or is it the v shaped graph with a horizontal line between x=2 and x=4? This problem is exactly like all the other problems I have to do so I have to be positive I am doing this one right. Please email me at <a href="mailto:jask925@yahoo.com">jask925@yahoo.com</a> with a quick sketch in paint. Thanks so much!!!!</p>

<p>It will still be a v-shape, but where x=3 in the normal v-shape, there will be a hole to indicate it is not part of the graph. Instead, there will be a point at (3,2). In other words, just draw it as if you were graphing it regularly, but add that hole where x=3 and put a point at (3,2)</p>