<p>if jkl are consecutive integers such that 0<j<k<n
and the units(ones) digit is 9 of the product
jn is 9, what is the units digit of k?</p>
<p>how do you solve this, and what is it asking?</p>
<p>are jkl the consecutive integers or jkn?</p>
<p>If JKN are consecutive integers (instead of “jkl”) then:</p>
<p>N = J + 2
JN = something with a 9 in the ones place
9*11= 99</p>
<p>Since K is in between those two integers, it must be 10.</p>
<p>I believe you meant jkn are consec intergers. 2 ways to solve I’ll post them seperately
j and n are 2 apart. try to come up with intergers 2 apart that when you multiply you get the units digit (ones place). 11 and 9 work. j=9, k=10. the units digit of k is 0.</p>
<p>the units digit of k is 0
what do you mean by the units digit of k is 0?
is it because the answer is 10?</p>
<p>since k can equal 10, the units digit of 10 is 0. 0 is the answer.</p>