October 2010 Math SAT Thread

<p>what were the dimensions for the triangle?</p>

<p>the greatest product one…
do u remember ? the one on the number line</p>

<p>w x y z blah blah.i think its a hard question to remember
but wasnt it A?</p>

<p>was “11-3x-y” answer choice B? ??</p>

<p>which triangle…5-5-6 or the 6-8-x?</p>

<p>^ it was A i think teddybear</p>

<p>

Wrong. There were not 290 freshman, there were 290 students in hall b. There were 225 freshman, which 45 is 20% of. The question asked for the amount of students in hall b, not the number of freshman.</p>

<p>Hey guys I skipped four and I am pretty sure I got everything else right (I am positive the dice one is 1/54 by the way) … I thought the math section was fairly a breeze but two of the ones I skipped were due to the time… can I still score around 680-700 in the math with skipping four assuming I got zero or one wrong?</p>

<p>wat was the one with the
the figure 1 area = 10 find the figure 2 area (shaded)</p>

<p>its like …part of the length was 3/2</p>

<p>i put 10 or something</p>

<p>Was one of the answers E. x > y for the t,x,y one?</p>

<p>Wasnt the outside triangle (the given one) 8/12/10?</p>

<p>Jollybjolly, I got answer choice B for that one.</p>

<p>i’m pretty sure the dice question was 1/18
the order does matter because if you’re doing 6^3 to get all of the possibilities, you’re including every order in there.</p>

<p>so 666 (which yields 18) has six different orders
and 566 (which yields 17) has six different orders. </p>

<p>so if you do 12/216 you get 1/18.</p>

<p>Ohhh! Ingenious. I never even thought of that. Grrr. Thanks guys!</p>

<p>We should embargo the dice question until the QAS comes out.</p>

<p>yoyoboy, I originally stated the answer was 225. To point out that 290 was incorrect, I said that 45 is NOT 20% of 290…so the answer has to be 225</p>

<p>waitttttt
the obtuse triangleeeeee</p>

<p>it can’t be 10???/</p>

<p>mikethechimp i just explained it…
there are 216 dice possibilities (6 values per die, 3 dice = 6^3 = 216).
there is 1 way to get 18 (first die is 6, second is 6, and third is 6)
there are three ways to get 17- any one die is 5 and the other two are 6. there are three DIFFERENT ways to get 17. so, of the 216 possibilities, the sum of the digits of 3 of those combinations equals 17, so 17 has a 3/216 chance of being rolled. 3/216 (from 17) plus 1/216 (from 18) = 1/54 chance to get EITHER 17 or 18.</p>

<p>if you’ve ever played craps, you know that you are most likely to roll a 7 because there are many possibilities to roll a 7; 1/6, 2/5, 3/4, 4/3, 5/2, 6/1</p>

<p>did anyone have a question with the scatterplot of the taxi drivers?
what was that?</p>

<p>no…that would make it a 6-8-10 right triangle, not obtuse…</p>

<p>The answer is def 290 for hall B, and 225 for the 9th graders. It asked for Hall B, hence the answer is 290.</p>