<p>The answer was one for absolute vaue</p>
<p>its definitely three not two for the a/b question… CONFIRMED</p>
<p>What’s the answer for dice if order doesn’t matter?</p>
<p>"2/3 4/6 6/9 "</p>
<p>Are u sure 9 was within the bounds?</p>
<p>“and 800 on math II subject”</p>
<p>Wow, that’s rather impressive.</p>
<p>What was the one about the area of the shaded figure. Origianlly it was 10 , so what was the new figure. IT WAS THE ONE IN WHICH THERE WERE 5 REARRANGED RECTANGLES. WAS IT 15 OR 10. THE PROBLEM WAS SORT OF AMBIGUIOUS , BECASUE PUTTING 10 WOULD BE TOO EASY</p>
<p>@mabsjenbu123, yes. The rule was that a & b were both integers less than 10, so 9 fits.</p>
<p>@frankeinsteinz,altamash
Thanks</p>
<p>did u guys get x^2 > 3/5y^2 ?? and i think it was 1/108, order didnt matter i think.</p>
<p>It was ten</p>
<p>did anyone get the one if a is greater than zero,</p>
<p>x^2 + y^2 = a </p>
<p>xy= a - 10</p>
<p>write (x+y)^2 in terms of a.</p>
<p>this stumped me for so long, ruined my mood for the next sections</p>
<p>in may i was -3 got a 730. did anyone else take in may. what do u think today’s was. -1,-2,-3</p>
<p>why was it 10. wasn’t the question ambiguous, as to whether it wanted even white spaces counted in the area. this is the exact wording “what is the area of the new shaded figure”. also if it was ten what would be the point of telling us the side was 1.5</p>
<p>If I had 2 grid-in sections, does that mean one was experimental?</p>
<p>@skikid419 I got -3 730 in May, too.</p>
<p>people make a consoidated list</p>
<p>@altamash
it was 10 because it was the same 5 rectangles and even though the perimeter was different, the area was the same. they gave us all that other info to throw us off</p>
<p>what is the answer of the problem which is about 5 rectangers originally put together, then arranged.
Is the area STAY THE SAME?</p>
<p>thnx skikid419</p>
<p>pretty sure area was the same for the 5 rectangle one</p>
<p>@skikid419: correct</p>