<p>^ i got 4/3</p>
<p>Are you talking about the max minus min parabola problem?</p>
<p>What was the quetsion itself?</p>
<p>FOr the question
xrad3>yrad5… what was the answer?? Was it x^2>y^2(5/33)???</p>
<p>"practically every1 missed the dice problem, due to its ambiguity, so either collegeboard is going to remove the probelm or make -1 800 "</p>
<p>No and no. It was clear. College board has successfully nailed you on not knowing how to do permutations problems properly, and thus you do not deserve the 800.</p>
<p>I said I got 4/3 or -4/3 (don’t remember which), but now that FacedAgain said 4/3, I’m sure that’s what I had.</p>
<p>I don’t think the dice problem itself will make -1=800, but honestly in general I thought it was just a harder math section. I got a 750 the first time and 800 the second time and thought those were both pretty easy, and this one I thought was the hardest. I’m guessing -1=780, -2=760.</p>
<p>@gensis
It was ax^2-9
for what value of a does the graph hit (-3,3)
still have it on my graphing calculator ;-)</p>
<p>@itsalaugh That’s correct.</p>
<p>for g(m+2) i got 2</p>
<p>Anyone remember one where the slope of two points was zero and you had to find the y coordinate of some point? was the answer 3? cuz it was 3-3/some#s</p>
<p>@boston1993 - "Yes-- 11, 12, and 13 are all correct answers for the 6-8-x obtuse triangle. I put 12. "</p>
<p>This was a grid in, I believe. I put 9. Because the problem stated that x was the largest angle, X would have to be the longest side. 8 - 6 = 2 and 8 + 6 = 14. Was this correct?</p>
<p>xrad3>yrad5</p>
<p>For that question, i got x^2 > 5/3y^2</p>
<p>***?</p>
<p>Altamash, it wasn’t ambiguous at all.
People who think its 1/108 should consider this,
The chance you’ll get anything from 3 to 18 is 1.
So the chance you’ll get 3 is
1/108
4: 1/216 (two ones and 1 two)
5: 2/216 (two ones and a tree, or 2 twos and 1 one)
6: 3/216 (3 twos, or 321 or 411)
7: 4/216 (331, 223, 421, 511)
8: 5/216 (611, 521, 431, 332, 224)
9: 441 531 621 333
And so on… And they should add up to 216. Which is not possible</p>
<p>
It was a grid-in, but the answer couldn’t be 9, it could only be 11, 12, or 13. A 6-8-9 obtuse triangle would be pretty funny looking. :P</p>
<p>^I thought it could be 10,11,12, or 13?</p>
<p>Btw, I put 11.</p>
<p>Yes, y=3 for the point.</p>
<p>And no, the triangle’s longest side could only be 10.01 to 13.99 (or 11 to 13 if it had to be an integer, but you get the idea.) If the side was 10, it’d be a right triangle, when the angle is clearly obtuse. If it was 14, you would have a line, not a triangle. So anything between 10 & 14.</p>
<p>Can’t be ten because it would then make a 6,8,10 right triangle when the problem stated x>90</p>
<p>here are a few of my responses that i remember…
this is NOT an answer key, these are simply the answers i got</p>
<p>btw for clarification i had only 3 sections of math so none of mine were experimental </p>
<p>B R G Y pattern- 119
starts with blue, green is #119 since 120 is a factor of 4</p>
<p>ratio problem of 2a / 3b with a&b is 3
with 2/3, 4/6, & 6/9</p>
<p>the hallway problem (the last one i believe for one section)
290 or something like that. 45 was not the answer because you needed to add the people in Hall B or something.</p>
<p>1.2 radii circle for the semicircle problem
12 length line / 5 = 2.4 diameter circle
2.4/2 = 1.2 radii</p>
<p>combination one</p>
<hr>
<p>first is constant, so you get
X 4 3 2 1 possibilities
4<em>3</em>2*1 = 24</p>
<p>2^n > 10n +58 problem
the answer is 8
let n= 7 and 2^n = 10n +58 so add 1 to 7</p>
<p>inequality one
|x+3| >= 5
so x<= -8 or x>= 2
and |y-4|<=3
so 1<=y<=7</p>
<p>the answer is 1 because the or graph contains neither 1 nor -1.</p>
<p>17-18 roll die one
4/216 or 1/54
because
666, 665, 656, 566 are all possibilities
4/(6^3) = 1/54</p>
<p>rt(A+B) =/= rt(a) + rt(b)
answer is 4,4
you get 2rt2 and 4 respectively i believe</p>
<p>15-(x+3x-y+2y+4)
answers -4x-y+11 (the actual answer was organized differently though)</p>
<p>the max min difference question
not sure of the exact answer, but you had to take the x values for the high and min points and subtract them with f() notation included in them.</p>
<p>30 degree slope
y=x/rt3
draw a 30 60 90 triangle
let the opposite side of 30 deg = 1
change in x = rt 3 change in y = 1
slope is 1/rt3
since it’s a line with center at origin, use y = mx + b where b=0</p>
<p>given: x^2 +y^2 = a; xy = a-10 ; what is (x+y)^2 in terms of a?
expand (x+y)^2 to get
x^2 + 2xy + y^2
substitute using first equation & get
a + 2xy
substitute again
a + 2a - 20
final answer is 3a - 20</p>
<p>x rt3 > y rt5
divide rt 3 from both sides
x > y(rt5/rt3)
square them
x^2 > (5/3)y^2</p>
<p>f(x) + 1 question; x=2x
let f(x) be substituted with 2x
final answer 2x+1</p>
<p>my curve predictions:
54 =800
53 =760
52 =730
51 =700
50 =680
49 =660
48 =650</p>
<p>10 isn’t possible cus it will get you a pythagorean triple(3/4/5 right triangle)</p>
<p>
</p>
<p>The harshest curve ever was:
54 - 800
53 - 770
52 - 740
51 - 720
50 - 710
49 - 690
48 - 680</p>
<p>Your curve is almost certainly wrong.</p>
<p>Does anyone know the answer to the last question on one of the grid in math sections? It was a quadratic equation with positive integer variables a and b and asked for the value of a. I skipped that question, but I’m not sure if it was experimental or not. Even if it was, I’d like to know how you solved that one cause I think I made it too complicated.</p>