<p>@cookcfc</p>
<p>“the difference between”… I thought it was the total hours spent studying in the four years I HOPE.</p>
<p>sorry it’s not 3, it’s 5 MW2</p>
<p>"With those numbers wouldn’t you get 1008? Also are you guys sure that the 1080 questions wasn’t multiple choice? "</p>
<p>I vividly recall it being multiple choice and it was 1080 a the answer. I remember because I almost answered 1008 because I wasn’t paying attention.</p>
<p>I vividly recall it being multiple choice and it was 1080 a the answer. I remember because I almost answered 1008 because I wasn’t paying attention.</p>
<p>^ do you remember the other answers if it was multiple choice?
I should have gotten on here immediately after taking the test, some questions are so fuzzy after a day</p>
<p>Anyone, what was 8000 the answer too?</p>
<p>@lonelywayfarer
You’re right. It was the total…</p>
<p>@Sasa
That was for the difference in something (revenue?) between July? and August. The equation was -2+30 and the numbers were 10 for July and 14 for August. (in thousands).</p>
<p>O ty I remember I put down 8000 for a problem, and then I thought I put it down for the comp problem for some reason lol, which would of been wrong. That clears things up. Still mad about the locker problem, didn’t put the total.</p>
<p>Does anyone remember the order and location of the letters for the “wx” problem. Was the order w, x, y, z ? Was w in the -1 and -2 range, x in the 0 and -1 range, y in the 0 and 1 range, and z in the 1 - 2 range?</p>
<p>
</p>
<p>The question didn’t ask for the value of x, it asked for 3x. Therefore, you had to multiply (5/9) * 3.</p>
<p>u know that x^2+y^2=a=x^2+2xy+y^2. your given the values for xy and x^2+y^2 so it ends up being 3a-20</p>
<p>jollyjolly, i put choice a, which was wx i think…</p>
<p>it was two negative numbers multiplied together to give the greatest product.</p>
<p>ehh, does anyone remember the exact question to the 5/3 answer?</p>
<p>@Phasmatis, the question was asking what was the total number of the students in hallway B. 225 was the total students only for grade 9. Therefore, 225 * .20 is 45, which is 45 kids in hallway B for ninth graders. Then, you had to add 45 with the other numbers in hallway B which equaled 290. Not 225. that’s the total number of kids in grade 9, not hallway b.</p>
<p>Was the answer to the dice problem 1/54?</p>
<p>whats the question with the answer on the consolidated list as PR = 8?</p>
<p>i dont’ remember some questions please help!!</p>
<ol>
<li>equation is 2x+1 when f(x)=2x</li>
<li>15 perimeter of triangle</li>
<li>2a-30</li>
</ol>
<p>Also, i have a new question to add.
It’s about which (a,b) would “not”(underlined) fit into root(a)*root(b)=root(ab)
a. (2,0)
b.(4,0)
c.d. sth like above
e.(2,2)</p>
<p>e was the answer. Actually, i dont think the above equation is the on the test but anywyas i remember for (e) 4 not eqaul to root 8 or sth.</p>
<p>@erick paperback books $1, hardcover $5. he spent $23 (i think) for a certain number of books (don’t remember).</p>
<p>yea it was e. (4,4) would not work</p>
<p>Crap, I don’t remember if I bubbled in 1080 or 1008. Hopefully I wasn’t ■■■■■■■■ as I’ve only missed 1 one math for sure as of yet.</p>
<p>Okay, I’m here to support the answer (1/108) for the dice question.
The question, as I remember it:
“You have three dice. What’s the probability that the sum of the three numbers rolled is 17 or 18?”</p>
<p>So what we’re looking for is the probability that there will be either
(A) Three 6s rolled
or
(B) Two 6s and one 5 rolled</p>
<p>Both (A) and (B) require two 6s to be rolled. The probability of rolling two 6s is (1/6) * (1/6). The third number rolled would have to be either a 5, or another 6. The probability of rolling a 5 or 6 is (2/6).</p>
<p>So, the total probability is (1/6) * (1/6) * (2/6) = (1/108)
That’s my two cents.</p>
<p>If you answered (1/54), I think you put too much thought into it. To get (1/54) as an answer, you’d have to do (1/6) * (2/6) * (2/6), which would create the possibility of rolling two 5s.</p>