October 2010 Math SAT Thread

<p>attakpack, the angle is 30 degrees. due to my deductive reasoning, i figured that 30 is, in fact, less than 45</p>

<p>@Webass: I put abs(xy) could not equal 1? Because based on my work, y could equal one, but not x.</p>

<p>was the parallel lines quest I and II only? number 7 in grid in section</p>

<p>CRAPPP, the lockers grid in section was so stupid. I did better on the experimental. ■■■. How do you even find the area of the triangle that had no height -__-?</p>

<p>what would a score of -3 omit 2 be…</p>

<p>the area of the triangle with the sides 5 5 and 6 was 12. Because if you would have flipped it so that 6 is the base. then you could have divided it by 2 so you have two triangles. then the base of one of the tirangles would be 6/2=3 and since its a 3 4 5 triangle, its just </p>

<p>A=2(1/2 <em>3</em>4)=12</p>

<p>the one with big absolute value signs around some x’s and y’s with inequalities</p>

<p>i got the answer cannot be 1</p>

<p>how the hell was this math section easy lol I found it medium for so me reason.</p>

<p>What was the last question to the 20 question section?</p>

<p>I remember picking B.</p>

<p>parallel lines 1 and 2, and the angle is 30 so therefore slope is less than 1</p>

<p>i don’t remember exactly what I got on the locker one, but you just take the 20 percent of 9th graders by adding the numbers in the first column times .2 and then get the total number of B lockers by adding the number of the second row. I’m sure it was somewhere around 290, but i know it wasn’t 225.</p>

<p>Hall B made absolutely no sense to me. I had 5 extra min to just focus on that one question and I still couldn’t even begin to solve it.</p>

<p>I feel stupid that I completely forgot that in the dice question, you do 6^3, not 6x5x4. Ended up leaving it blank :-/. In retrospect, such an easy question.</p>

<p>what did you get for that question with the line that makes a 30 deg angle with the x-axis? I know the equation wasn’t B) y = x/2, but that’s what I put. Pleeease tell me this section was experimental.</p>

<p>Remind me the question that was right before the locker question?</p>

<p>Was the probability of 3 cubes summing up to either 17 or 18: 1/54?</p>

<p>For the set of parallel / perpendicular lines (l, m, r, s), I said I and II only.</p>

<p>I think I had the math section that jollybjolly posted answers to. I don’t think they were experimental because I had an experimental writing…</p>

<p>@borkoborkoborko
you have to do the special case for a 30 - 60 - 90 triangle
i dont have the rations memoriazed theyre on my calc
but the answer was X/3^.5</p>

<p>look the for the thirty degree angle if you draw out the triangle
you get the length of the x axis = xradical3 and the height is x so you find slop which is rise over run= x/(xradical3) so slope is 1/radical3
it asked for equation of the line not the slope
so equation= y=x/radical3</p>

<p>:)</p>

<p>I also got I and II only for the parallel/perp lines q.</p>

<p>for the grid-ins anyone get these answers:
5/3 (solve for x and find value of 3x)
1.2 radius of each circle</p>

<p>for the parallel/perpendicular lines i got I only
anyone get that?</p>