<p>Hey guys wasn’t the x^2-2^x only for positive real values of x and in that case wouldn’t x^2>2^x not be a possibility. If that isn’t the case, heyhihello’s answer is correct.</p>
<p>Trenchlord
All three cases are possible is what i marked. You can see for x = 4 , theyre equal…
Out x = 3 you get 2^x lesser than x^2
And put a very large number (10000), you get the opposite. So all three cases possible.</p>
<p>I don’t think the 2^x and x^2 was I, II, and III because when x>2, 2^x is much greater than x^2</p>
<p>Hendrix, son, put 3</p>
<p>All three were true, and I found that during the test, but for some reason, I don’t remember if I put the option for all three down in the answer sheet…</p>