<p>I don't remember what it was, but I think it involved work, in which case W=Fd so W=30</p>
<p>The answer 'tis correct. </p>
<p>Kinetic energy=work=Fd=10*3=30 J</p>
<p>Pitch does associate with frequency, but they asked for a quantity that is associated with the "fundamental frequency". I still think it is resonance</p>
<p>i also was stuck between that and pitch. someone should explain.</p>
<p>Yes, someone should.</p>
<p>Also, on a slightly different note, what is the estimated curve? Assuming all questions went answered, how many could one get wrong (probably) and still get 800?</p>
<p>Fundamental frequency = pitch, no?</p>
<p>not just association with frequency</p>
<p>Oh, wow. I completely forgot that formula. Thanks. Did anyone like the trick question that was 72?</p>
<p>What was it?</p>
<p>This</a> is a bit ambiguous, but I think it suggests pitch over resonance.</p>
<p>Mr. Prez, it was the one about the force and friction. I think I may have gotten it wrong, though, so it wasn't a trick question.</p>
<p>what did everyone else get for the questions posted on the first page of this thread?
not sure if i got the same answers as everyone else</p>
<p>like comparing the values of the two columns, the proton shot at the positive plate, the inducing emf one, graph of intensity of light...</p>
<p>bump</p>
<p>i'm stressing out over whether i should cancel my score or not.</p>
<p>Just relax.</p>
<p>For the proton shot at a plate question, was the answer kinetic energy (I don't remember what the exact question was)?</p>
<p>Also, for the capacitor one, was the answer something like 40 x 10^-4 (yeah, it wasn't even in "proper" scientific notation)?</p>
<p>amciw - wasn't the answer to that one fcosx?</p>
<p>Yes, yes it was. I got it wrong. The capacitor one, was, I thought, in incorrect notation. It made me second guess myself, but then I meant with what felt right.</p>
<p>i'm pretty sure the answer was 20 * 10^-4 because charge was 2 microfarad</p>
<p>f/cos was the other answer, i think</p>
<p>Well, I know it was something to the 10^-4, and I doubt I screwed up my 3rd-grade math, so I certainly hope I got it right.</p>
<p>And f/cos? Why? Constant velocity means the horizontal component of the applied force and friction cancel each other out and are therefore equal in magnitude. So shouldn't it be fcos?</p>
<p>nah, its at an angle.
f=some frictiona force
then the triangle shows this cos x= f/ (our actaul force)
our actaul force=f/cosx
PLZ correct me if i am wrong!</p>
<p>wat was the answer for this?? </p>
<p>Two blocks of different mass and different temperature. Where does the heat flow? </p>
<p>Which ones are the correct diagram about the direction of heat flow.</p>
<p>I, II, or III?</p>
<p>I put II and III only I think...</p>
<p>Uh doesn't heat transfer only from hotter to colder? I didn't see how mass was relevant in this problem</p>
<p>MrPrez, you are correct. Heat doesn't transfer spontaneously from a lower-temperature medium to a higher-temperature medium.</p>
<p>The equation Q=mc(deltaT) applies only when heat is definitely being transferred.</p>