yea idk if i got that lol thanks! -.44 looks familiar but idk. wat about dp/dt mc one about population …wat about the dy/dx problem (last one calc mc) i already asked but wat did everyone else get
dp/dt mc was whichever one had Kp(250-p) or w.e the carrying capacity was
@CalcKeddddd But I don’t think you can just do that and consider it as 0 because m varies, depending on the x and y values. I know it’s “constant” but it’s not really constant until you put the x and the y values.
And there can only exist one y=mx+b, since differential equation is all crazy, so it can’t be linear… meaning they wanted a tangent point at a specific point.
I may be wrong, I don’t know, but it doesn’t sound very logical to take the derivative of m for me.
dy/dx i put graphs 1 and 2
I also put y=1 and b=1 but in hindsight that was far too easy and i don’t think they would have bothered asking that, but i don’t remember the exact wording of the question well enough
@CalcKeddddd My only concern with the “2” being the answer is that, the answer varies depending on your x and y, unless I remember the problem completely wrong…
I remember i was debating it in my head as well, i just reasoned that if it was some random Y=(Ysomething)+x, and you took derivative to find dy/dx, the derivative would be completely dependent on the y because the x would become just +1, idk if how i explained that made sense, but i wasn’t 100 percent sure on that one
And unlike in graph 3, as each y value changed, dy/dx changed, therefore you could say it is depending on y
@CalcKeddddd I’m still talking about the other problem, the FRQ lol.
Oh crap, my bad. Yea, if i remember correctly, it said the point 2,3 was part of the original function, and if they intended the point 2,3 to be on the line y=mx+b, then 3=2(2)-2 would not work. I don’t really remember how the question was worded or if these are even the right numbers tho
@CalcKeddddd @sjwon3789 my friends used the point from c in that part… I didn’t even think to do that. Since with non separable Diff Eqs you need a point… If that is what was supposed to be done I say it’s bad planning on CB’s part to make you infer to use part c info for part d without direction to do so, esp with the way the pages are broken up by section
@CalcKeddddd My argument is that the linear equations can vary depending on x and y, meaning those (2,3) HAVE to be the given coordinate points that you have to use. I mean, they don’t even work in the y=mx+b; why don’t they?
It’s because the differential equation is a slope and it changes depending on the x and y, so m cannot be fixed; it changes depending on the x and y. Under the assumption that part c is involved, it makes sense, but it doesn’t if you go by what laGrange is saying.
I may be wrong, but this is just what I’m thinking. We’ll figure out tomorrow I guess haha.
@shakespearedoc I agree that CB did a bad job on this. I think they actually done similar things in the past though. I kinda assumed it to be the case because it didn’t make sense if you didn’t… I needed a point and I looked up and found it lol.
Agreed, the people who used part c probably got b=1 m=1, those who did it using 2nd derivative got m=2 b=-2. What should have been a relatively ‘easy’ problem will probably mess > 50 percent of the people up.
for dp/dt mc one was it b? thanks a lot!
What’s calculus? -.-
If the question were asking for the tangent line to dy/dx, then you would need a point, which is why using the information from C would make sense. I just thought the question didn’t say anything about a tangent line. It said that y=mx+b was a solution to dy/dx. If the answer were y=x+1, you only get one point that satisfies dy/dx=2x-y. (2,3), which would make the linear equation a tangent line to one of the curves. y=2x-2 is the solution for dy/dx because no matter what you plug in to the linear equation, dy/dx will be satisfied.
@laGrangeError If that’s what the problem said, then I may be wrong then lol
im so sad that i forgot a plus c and i didnt add a 30 to the integral and that i forgot the speed paramrtric formula lolol im probz gonna get a 1 but YOLO
On the dy/dx frq I just said dy/dx(2,3)= 4-3= 1, then I just used point-slope form to find b, that seems right, right?
@chihuahua1 If you got a single question right, you probably got a 2. Stop exaggerating.