What I did:
a.) Ratio test and got that R is 1/3
b.) Took derivative of f(x) to get 1 - 3x + 9x^2 - 27x^3
Since it’s a geometric series, r = -3x. To get the rational function for f’(x), you use sum formula a/1-r. So: 1/(3x +1)
c.) I took the integral of 1/(3x + 1) (also finding that the + C is 0) and multiplied by the number of terms from the e^x series that the problem asked for. Wasn’t sure if this is the way to do it, but I feel it makes sense.
@aar2697 - I don’t fully remember my answers, but I know I got the same thing for you for a. Part b and c look familiar- I think I got the same thing as you for that also.
@vakiii - I don’t remember that problem coming up in the free response. However, I tried the question and came up with -6y/(3y^2+1)^3.
Now I’m pretty sure I did number 6 wrong. I got 1/3 but, For part b, when asked to express f’ prime of a rational function for |x| < R, I just derived the general term for f to get the general term for f prime. And for part c, I just took the terms for e^x and the terms they gave you for f at the beginning of the problem, and multiplied them together, I probably only got a 3 for this problem…
@oblivion96 When you write out the Talyor Series of f’, you recognize it is a geometric series and therefore you can write it in the form of 1/(1-r) (in other word, a rational function or a quotient)
@taiocruz I’m pretty sure you guys are both wrong. Several friends and I all got x - x^2/2 + 2 x^3. I just plugged this into mathematica as well and got the same answer. You just have to multiply the first 3 terms of the series of e^x with the series of f(x) that they give you.