<p>@covertcognomen</p>
<p>double w00t! nice find. looks like that’s an extra point for me! using appass i total like 105, and that’s in the worst case scenario. with the (hopefully) slightly lower curve i can get that 5!</p>
<p>I feel really terrible after seeing killerskullz’s answers. I hope I will be able to get at least a 3 
It’s either my MC saves me, or it dies trying</p>
<p>I think that Killerskullz did a fantastic job… except with number 1… Biii) and Cii) cant possiby be right</p>
<p>I keep playing around with appass, realizing that I could have only gotten about 4-7 points on each FRQ, but with a solid MC (60-70), I’m borderline 4/5. Every time I look at another free response question, I realize I missed another point, either sig fig or something else, at least there’s a lot of easy points</p>
<p>Hope this helps. Did this very quickly so there might be a couple of mistakes. Feel free to comment if you think you see a problem.</p>
<p><a href=“2013 Free Response Guidelines - Google Docs”>2013 Free Response Guidelines - Google Docs;
<p>@deuro I checked with numerous people, and so far no one has called me out on those answers… Maybe your calculations were wrong? D:</p>
<p>@hypno for 6e, only the H from H2O and O from methanal would bond because hydrogen bonding only occurs with Hydrogens that are attached to an F, O, or N. Not a carbon. And I posted the answers a few pages back as well, thanks for adding!</p>
<p>I thought Ksp meant that it would be Ksp=4x^3 where x is the concetration of {F-}</p>
<p>Killer, your 1bii and iii are wrong. To find [F] the expression is 3.5E-11=[.1][2x]^2. It’s [2x]^2 because F’s coeffiecient is 2. This then makes [F]= 9.4E-6 thus changing the answer for biii.</p>
<p>@deuro, that’s only if both concentrations are unknown. But here, we are given the [Ca+2].</p>
<p>@BIazer, check with the link hypno posted. It matches up as well. I am fairly confident we did the question correctly.</p>
<p>what about aiii</p>
<p>we only get F</p>
<p>@deuro, since the water was distilled, there were no extraneous ions in it. So the [Mg+2] and the [F-] were 0. Then, as the solid MgF2 dissolved, it dissociated into Mg+2 and F-. There is twice as much F- as there is Mg+2. So if they give us [F-], they also essentially gave us [Mg+2]. Understand?</p>
<p>Can someone determine how many points each part of the questions would? Just an approximation?</p>
<p>Usually the calculations would have 2 points, one for setup and one for answer, the explanations would have 1 for short explanation and 2 for a lengthier explanation in which multiple concepts need to be discussed, 1 for just a simple statement or drawing and then -1 if there are sigfig errors, which is hard to avoid when short on time, so likely you will have.</p>
<p>they only grade ONE problem on the whole test for sig figs. If you get lucky, you may get no points off at all because of sig figs.</p>
<p>The hydrogen bond is with only one hydrogen, I can confirm that (asked an expert).</p>
<p>@killerskullz, that sounds right, I couldn’t remember the details, you say they choose only one problem at random, so if you miss every single significant figure, you would miss one more point on the whole FR part?</p>
<p>I got different answers than Killer for 1, and my other friends that did AP chem with me got the same answers as me so… i dunno.</p>
<p>Is there a google doc for MC?</p>