@Frigidcold Here http://www.chemguide.co.uk/physical/basicrates/surfacearea.html#top “he more finely divided the solid is, the faster the reaction happens. A powdered solid will normally produce a faster reaction than if the same mass is present as a single lum”
@andyis thank you! see frigid!!
@APScholar18 Decreasing pKw, less products, less H30+, pH=-log[H3O+]
@andyis I completely agree, grinding it does produce a faster reaction, I still don’t think it affects the rate contant though. 
@taw1020 - THANK YOU. Hopefully people will actually understand what I was trying to say now. 
Everyone, go read that explanation.
Any good websites for acid/bases review? I’m doing some FRQs and I’m struggling a lot LOLOL i always sucked at acid bases and need some kind of basic review
@glasshours thanks bruh I like yours too
@Mathman97 I don’t see. I see that it produces a faster reaction, which I knew all along I’m talking about the rate constant.
Yea it’s only 6:08 where I live so I’m still up for last minute cramming if you guys are lol
Does anyone know how the FRQs were revised? The multiple choice questions are obviously more conceptual, but I can’t tell the difference between the 2012 FRQs and 2013/2014 ones…
Can anyone explain why this is false? It’s from the collegeboard FRQ but i didn’t really understand the explanation; The pH of a solution prepared by mixing the 50.0 mL sample of 0.20 M CH3CH2COOH
with a 50.0 mL sample of 0.20 M NaOH is 7.00.
Anyone know specifically know how to do 2014 MC #29? I know the correct answer, but I don’t think my reasoning is correct. Can’t remember if you multiply or divide the constants. 
@Frigidcold - K3 = K1+2K2
@lkim97 - The pH at the equivalence point is only 7.00 if you’re titrating a strong acid with a strong base (or vice versa)
I think you’d just set up a reaction and convert to moles and subtract @lkim97
@glasshours If you’re sure. Could have sworn it was something else… Hmm…
@Frigidcold ok let me convince you then.
the equation is rate=k*[x]
if we agree sa changes rate, then it would have to also change k and/or concentration, since we know it does not affect concentration, it would have to affect k
Okay, I’m going to stop doing FRQs now and just hope for the best at this point. May we all get 5s and may the gas/electrochem questions be easy
@lkim97 CH3CH2COOH is a weak acid and NaOH is a strong base so if equal amount are added the pH will be more than 7.
@Mathman97 - Last thing I’m going to say about this: read the explanation that @taw1020 wrote. Can we please stop discussing this?
frigid for those, if you multiply everything by two, then you square, if you reverse, you take the inverse