Official December SAT Math Thread

<p>No, it was B for the unfolded paper. It had to have a center in it because it was folded symetrically three times. Try it now. </p>

<p>15 kids, avg age is 17, oldest is 20. which is correct,
I. 3
II. ?
III. 17</p>

<p>Anyone get a question like f(x) = 0 and the choices were 5 graphs?
1 line was diagonal and some were parabolas ... ?</p>

<p>I didn't have that one. More questions
f(x)= X^n + C If F(1)=3 & F(?) =? what is one possible value for n? I put 3</p>

<p>if sum of all number from 2-202 inclusive is (some number)
what is the sum of all numbers 4-200 inclusive?</p>

<p>One had two cirlces over each other. One radius 5 one Radius 3. What is the distance between two points on the picture. I put not determinable.</p>

<p>I had the question with the median age being 17. i think the answer was all 3 of the choices?</p>

<p>I didn't have that one. More questions
f(x)= X^n + C If F(1)=3 & F(?) =? what is one possible value for n? I put 3 </p>

<p>---Same</p>

<p>if sum of all number from 2-202 inclusive is (some number)
what is the sum of all numbers 4-200 inclusive?</p>

<p>I think it was like 204 less than the number they gave.?</p>

<p>One had two cirlces over each other. One radius 5 one Radius 3. What is the distance between two points on the picture. I put not determinable.</p>

<p>I put 1</p>

<p>i had that one And432rew, it asked where there was only one value for x (not worded like that) it was the straight diagonal going up (only touched the x-axis once)</p>

<p>hey I put 96 to that question Why is it 112?</p>

<p>Alleysome, how did you determine that answer?? Without actually measuring it, it is impossible to algebraically determine the answer. even if the answer was exactly one, you would have to put "indeterminable" just because the test is designed to be done without a calculator or any other resources.</p>

<p>Because when you cut away the area, the new dimensions are 4 by 4 by 7. Cutting away the one inch at the base width-wise adds to the height of the cube. It's easier seen on the diagram.</p>

<p>I put it cannot be determined for those overlapping circles, because think about it.. even if you know the radius, the distance between those two points they gave will change depending on how much the circles overlap, so we need at least one more value besides the radius to determine anything.</p>

<p>Then again someone might come out and prove me wrong...</p>

<p>@ Schitz We are not talking about the same question. I wish I could draw it right now and put it up here, sadly that is for another generation of CCers.</p>

<p>Since you took the same test, judy, do you remember what you got for the last grid in? I remember I got a 6, though for the life of me I can't remember what the question was (although I remember it involved square roots). It was something like, what value of t satisfies f(2t) = 2f(t); but I can't remember what the function was.</p>

<p>ach44 - was talking to judy about the cube question :D</p>

<p>Does anyone rember putting 10.3 or 10.6 as an answer for the gridin??
Another grid in was like 4343 (not right numbers)</p>

<p>ach44 - i remember putting in 4949 for population of 4242 that is 6/7ths of what it used to be in 1995</p>

<p>I got this question for a grid in.</p>

<p>The sum of the 12 edges on a cube=4</p>

<p>I take it that each edge =.3, so are you just supposed to use Legnth Width Height to solve?</p>

<p>California-Bolt i got .037 for that cube question</p>

<p>o thanks schitz god damn now 2 wrong in math, o well i already have an 800 in math :) but yes ach44, I had 6</p>

<p>ach44</p>

<p>For the median 17 I, II, III, i think its all 3</p>

<p>I had the question about rotating the line 210 degree, was the answer A? counting counterclockwise, 30 degrees in the second quadrant?</p>

<p>there was one question with 75 numbers or something like that dealing with the median. all i remember was i put 113.. anyone else put something different?</p>