<p>yea its only "y" u got it right</p>
<p>Circle split by two lines that were equal to diameter, which created 4 regions. Two regions were shaded, and it said something like the area of the shaded regions combined was equal to the average area of the nonshaded regions. And it asked for the angle of x, which was the angle of one of the shaded regions.
I got 60 degrees. Was that right?</p>
<p>60 degrees is right</p>
<p>Okay, what about the one that was like, 60% of the population is in Asia and 20% of the land mass or something, and then if there were an average of 1000 people per square mile in the world, how many in Asia? Then the answer choices were like, 200/300/600 and so on or something like that. I'm sure it was really easy but I honestly could not even think of where to start.</p>
<p>for that, i got 60/.2 which is 300:1</p>
<p>I also got 300 for the population one... 60/.2 = 300</p>
<p>300 is correct</p>
<p>yay i got 300 for that one also!</p>
<p>HOw about the question with the absolute value answer choices? Something about a number line, with X, and each value is five away from X. I got answer C, which I got by plugging in numbers. What'd u guys get?</p>
<p>each value was 4 away from x</p>
<p>are you sure??????</p>
<p>I thought it said 5!</p>
<p>Was the answer C though???!?! omg i got it wrong then!!!!!!!</p>
<p>Was it like -1 and 9 as the distances to solve for?????? in that absolute value problem?</p>
<p>i think it was |x-4|=5 was that c? not sure but i remember it was -1, 9 and the line was at x=4</p>
<p>The number line problem asked which answer choice MUST be true so that xyz is negative:</p>
<p><-----x----y----z----></p>
<p>I. all are odd
II. x<0
III.yz>0</p>
<p>Eliminate I, because you don't need to know whether the number is odd or not. I'm not sure if I remember reading whether the choice said "all are odd" or "all are negative." Regardless, it's wrong either way.</p>
<p>For xyz to be negative, x MUST be negative. If not, then that means all three numbers are positive and the result is negative. So II is good.</p>
<p>Now, as ldu1207 pointed out, there are two possibilities for xyz<0:</p>
<p>1st possiblility x (negative) y (positive) z (positive)
2nd possibility x (negative) y (negative) z (negative)</p>
<p>either way, when you multiply yz, the result is positive.</p>
<p>So, the answer is II and III. I just realized that I didn't see III as an answer when I first took the test and just put II. That's two wrong now since I made another stupid mistake that was straight plugging in a number in a sequence. :(</p>
<p>Mike you are wrong. They all have to be odd to make the whole thing odd. </p>
<p>Lets observe: 2x3x3 (1 even, 2 odd) = EVEN
2x2x3 (2 even, 1 odd) = EVEN
2x2x2 (3 even) = EVEN
3x3x3 (3 odd) = ODD</p>
<p>The answer was I, II, and III.</p>
<p>O btw it was xyz is an ODD NEGATIVE integer. That's where you messed up and thought that it was totally irrelevant to the question.</p>
<p>I don't remember getting a line problem one, was it a multiple choice or grid-in? I also only got one math section...did you guys get 2? haha maybe it was one of the two I omitted in the grid in, but then again you have I , II, and III so it must have been multiple choice.</p>
<p>oops, i did misread it. btw, do you remember what section that was. Hopefully it was experimental.</p>
<p>it's not experimental. I had that question and my experimental was CR.</p>
<p>What abou the grid-in that said
x is greater than or equal to -5 and less than or equal to 0; y is greater than or equal to 0 and less than or equal to 5. And it asked what the least possible value is for lx-yl
I got 0. Was that right or did I misread another question?</p>
<p>It actually asked for the least possible value of 12/|x-y|, so you would have been looking for the greatest value of |x-y|. The answer was 12/10, or 6/5 (haha I can't believe I still remember this).</p>