****OFFICIAL JUNE 2014 SAT MATH II THREAD****

<p>And you can get from 700 to 800 on the Barron’s to actual, but no one can really tell you for sure.</p>

<p>Hi, can anyone helpe me with this Math II question?</p>

<p>When a certan radioactive element decays, the amount that exists at any time t can be calculated by the function E(t)= (-t)/(ae^1000), where a is the initial amt and t is the time in years. how many years would it take for an intitial amount of 600mg to decay to 300mg?</p>

<p>A. .5
B 500
c 693
d 1443
E 5704 </p>

<p>Thanks</p>

<p>Are you sure that’s the formula? </p>

<p>Plug in the numbers, set initial amount to 1, final amount to 1/2, and solve.</p>

<p>Does anybody have links or a pdf to a practice test? I just found out there was only one in my Blue Book, and I did horribly in it </3… I made so many careless mistakes, ahhhhhhghhh!</p>

<p>There’s practice problems online… Not sure about PDF’s though.</p>

<p>Are the Sparknotes ones accurate, you think?</p>

<p>Haven’t looked at those.</p>

<p>Can somebody do this problem for meh :D? </p>

<p>P(x) = x^3 + 18x - 30 has a zero in the interval
a.) (0 , 0.5)
b.) (0.5 , 1)
c.) (1 , 1.5)
d.) (1.5 , 2)
e.) (2 , 2.5)</p>

<p>I’m a bit confused because they don’t look like “zeroes” to me O_o…</p>

<p>You find the zero by graphing the function and finding the rough areas of where the zero is, and then you select the intreval (answer) where it is. So if the zero were 0.3 you’d answer a</p>

<p>The zero is like (0 , 1.48). </p>

<p>Does anyone know where to find the SparkNotes practice tests online? I’d really like a confidence boost after having taken the Barron’s tests…</p>

<p>Go on their website, they probably have a link.</p>

<p>Reposting previous question with more clarificatoin</p>

<p>Hi, can anyone helpe me with this Math II question?</p>

<p><a href=“http://■■■■■■/9cCYN/dc6e1aa9a6.png”>http://■■■■■■/9cCYN/dc6e1aa9a6.png&lt;/a&gt;
When a certan radioactive element decays, the amount that exists at any time t can be calculated by the function E(t)= (-t)/(ae^1000), where a is the initial amt and t is the time in years. how many years would it take for an intitial amount of 600mg to decay to 300mg?</p>

<p>A. 0.5
B. 500
C. 693
D. 1443
E. 5704</p>

<p>Plugging the values in, you get: 300= (-t)/(600e^1000)
or you can try (.5)=(-t)/e^1000 , like nephew mentioned.
However, if you try to solve for t using your calculator there’s an error: overflow. My Question is how do you solve for t then? The answer is C, 693, by the way. This question is from the 1995 Math II test.</p>

<p>Is math 2 at the same level as ap Calc? I’ve only done one full year of precalc but I’m considering doing some ap Calc in the summer to prep for next year</p>

<p>Nope, there’s some limit stuff, but that’s the simple ones. </p>

<p>@hagzz are you sure its e^1000 ? thats a really big number</p>

<p>facepalm. I kept reading the problem as (-t)/(ae^1000) instead of ae^(-t/1000)</p>

<p>This weekend, people.</p>

<p>DS is hovering around 690 on Barron…</p>

<p>I just scored a 760 on the Barron’s Diagnostic Test after getting an 800 in the Blue Book. The topics in Barrons are much harder, including straight foward limit definitions, conics and polar coordinates. Thank god for my awesome yet very difficult precalc teacher. </p>