<p>how do you do number 58 for the math section. I know the answer is G.</p>
<p><a href=“http://media.act.org/documents/preparing.pdf[/url]”>http://media.act.org/documents/preparing.pdf</a></p>
<p>how do you do number 58 for the math section. I know the answer is G.</p>
<p><a href=“http://media.act.org/documents/preparing.pdf[/url]”>http://media.act.org/documents/preparing.pdf</a></p>
<p>use the 6th and 10th term to get the common difference -> 1.25
Then just find the first term by subtracting 1.25 from the 6th term the appropriate number of times, then add, etc.</p>
<p>thankss! i had 1.25 but for some reason i figured 1.25 was the first term in the sequence.</p>
<p>@ketann
In an arithmetic sequence, terms are equidistant on the number line from each other. They gave u the 6th and 10th term</p>
<p>t6 = a + 5d = 8 and
t10 = a + 9d = 13 or
t10 - t6 = 5 = 4d or d = (5/4) and a = 8 - (25/4) = (7/4)
So required sum t1 + t2 +t3 +t4 = (4/2)<em>[(7/4)+(7/4) + 3</em>(5/4)] = (4/2)*(29/4) = (29/2)</p>
<p>thanks. i had 1.25 as the number that it increased by but i assumed wrong that it was also the first term lol. butt did ya get ya score? btw, did you see the curve for the math on that link? ohmyyyygod. the one on june was harder than that one.</p>
<p>can you also explain #56? the answer is J.</p>
<p>The two triangles have two of the same side lengths (x and y). The included angle is 70 in one and 110 in the other. Using the sine rule to get the area gives us 0.5<em>xy</em>sin(70) for the first triangle and 0.5<em>xy</em>sin(110) for the second triangle. Sin(70) and sin(110) are the same thing, and so the areas of the two triangles are the same!</p>
<p>I think this is a problem that is actually extremely easy, but its disguised as a difficult question. Since the x and y lengths are the same, that third side is related to the lenghts of x and y. The rule for triangles side lengths applies (I think it’s something like when you add two sides they must be greater than the 3rd and when u subtract them they must be smaller than the 3rd). Since the base gets larger and the height gets smaller in the triangle, it’s just a relative question…the area stays the same.</p>
<p>I just tried law of sines…agar has the correct explanation.</p>
<p>Glitch worked! I was getting transaction could not be completed…message for last two days but tried about 30 min ago and it worked. Used NSpire shortcut. Thanks!</p>
<p>agar how is sin70 and sin110 the same thing. and what “sine rule?” law of sines?</p>
<p>Supplementary angles always have the same sine (I guess this is an identity?).</p>
<p>I meant the equation for the area of a triangle, which uses sine. Not the sine rule/law of sines.</p>
<p>A = 0.5<em>sidelength</em>sidelength*sine(included angle)</p>
<p>dam i’m lost haha. only question i dnt get. But i think it’s a bad question. I may be over thinking it idno…</p>
<p>What’s confusing you? I could try to clear things up</p>
<p>OHHH, i got it. the bigger the angle, the longer the base is but shorter the height; therefore, .5bh will be the same.</p>
<p>i was def over thinking it</p>
<p>Does anyone think it’s possible/experienced scores coming out tomorrow morning through the glitch for people who haven’t gotten their scores yet?</p>
<p>I followed the instructions exactly and all i got was: “did not match any documents”. Hmmmm…</p>
<p>i really hope my scores get posted tonight.</p>
<p>Ugh I give up on this glitch. Just going to wait till midnight tomorrow!</p>