<p>are people sure that the triangle question with sides 4 and 6 and angle of 42 is not possible?</p>
<p>I'm kinda sure that there was a limit for that problem because I graphed it (...yeah such a waste of time..)during the test, and there was a limit. It was approaching to a certain number from the both sides.</p>
<p>What was the answer to the imaginary number question? I got a point down 2 on the y axis.</p>
<p>being able to cancel out those factors indicates the there was a discontinuity at a particular point and that you just removed it - there are no jumps or asymptotes with different behaviors.</p>
<p>ok so if there was a limit, i'm down -2. which is still an 800 :)</p>
<p>i got the inclusive 20 to 30 problem wrong. i put 5/11, because i forgot to count 30 :[. missed where it said "inclusive"</p>
<p>sides 4, 6 and angle 42 is possible.. does anybody remember the question?</p>
<p>yeah you could easily put 6/10 if you weren't careful enough - definitely a tricky one.</p>
<p>lostinbalt whats the problem that said inclusive ?</p>
<p>it said even numbered 20 to 30, inclusivly, find out of 11 total.
so 20, 22, 24, 26, 28, 30
= 6/11</p>
<p>i put 5/11 cause i didn't read "inclusive" which means, including 30. since it said in the actual question 20 to 30
stupid college board shenanigans, trying to trick everyone</p>
<p>is xyz plane or straight line? I put straight line but after reading the comments, i think it could be plane. But wasn't the question in the beginning, therefore suppose to be easy... idk maybe not.
so #49, triangle wasn't possible? i put two but wasnt sure.
If I got those two wrong, -2.</p>
<p>plane, because on an xy coordinate it would be a line. thus on an xyz it would be a plane</p>
<p>I put plane. points are x = 4, y = 0, z = 0.</p>
<p>So just think about an imaginary graph, the z-axis would be coming out toward your eyes. connect that zero with the y zero, and the x 4, forms like a triangular plane.</p>
<p>I wouldn't use your username. SPMorgan, they can deff. tell who you are. Sarah Peter Morgan, perhaps? How many SMorgans took the SAT today? Good thing you didn't put your location in your newly created profile</p>
<p>The odds of cancelled scores = 0.</p>
<p>I thought it was fine to discuss it on internet/e-mail?</p>
<p>and the plane, they didnt say y=0 nor z=0</p>
<p>lostinbalt, something in me doubts that their name is Sarah Peter Morgan... :P</p>
<p>anyone knows the answer to the problem where they ask you what the length of line BD is ? ( the one with circle and radius 1 )</p>
<p>they didn't say y = 0 or z = 0, but thats what i assumed because if it was in equation for x + y + z, it would be 4 + 0 + 0, thus y and z are considered to be 0. If they aren't zero, then what are they? if they were anything but zero, it would still be a plane. It can't be a point or line if they're talking about an xyz cordinate system. </p>
<p>I skipped the BD problem. So -2 and omit 1 so far.</p>
<p>what was the one with the area of the right circular cone? and there was an arithmetic sequence problem that was 7, right?</p>
<p>the volume of the cone? i think it was 1/3pi(r^2)*h where h = 10... forgot what the answer was though. there was another cone problem i think but it was 4/3pi(3^2) + 4/3pi(4^2) + 4/3pi(5^12) i think the answer came out to be 16 for that one.</p>
<p>i forgot what the arithmetic sequence ones were, there were many.</p>
<p>
I got 2.37.</p>