<p>More precisely, it’s actually the rule of 69.3. Hence 69.3 * 1.5 is closer to 105.</p>
<p>Does anyone remember the coordinates for the polynomial function graph question:
There’s (2,9) (-2,9) (-2.5,-13.5) and what else?</p>
<p>The last one was more like (2.5, -13.5). It was like a parabola except the last value (x=2.5) plummeted below the x-axis.</p>
<p>What about the other two?</p>
<p>Guys the 46 or 47 question that asked for the sin or cos for the angle bounded by a liner equation how to solve it?</p>
<p>Another general question
Can I take the test outside my country? My country doesn’t provide SAT2 in Jan</p>
<p>For the question that gave the graph of the terminal side of an angle and then asked for the secant. This is what I did:</p>
<p>y + 5x = 0</p>
<p>y/x = -5 = tan(x)</p>
<p>tan^2(x) = 25</p>
<p>sec^2(x) = tan^2(x )+ 1</p>
<p>sec^2(x) = 25 + 1 = 26</p>
<p>sec(x) = sqrt(26)</p>
<p>Answer = -sqrt(26) [secant is negative in the second quadrant]</p>
<p>No one has contradicted the answer so far, and I’m pretty confident its correct.</p>
<p>Cause the interest is compounded monthly!</p>
<p>I got pi as well</p>
<p>should be 25 as it is the only number not divisible by 360</p>
<p>Dang. Exact same thing happened to me actually.</p>
<p>yeah that’s what I got</p>
<p>May was the right answer for month</p>
<p>Yeah I think May was right because the gap between june and 32 degrees is very large. May is really close to 32 in comparison to june so it had to be between may and june. Also they mentioned that it was the first day of may and the first day of june. Therefore, it could’ve happened on like the 20th day of May for example.</p>
<p>It think it was July not May. Did you make sure your calculator was set to Radians before you graphed the function (assuming you used your calculator for this). If you check the Table feature on your calculator you can see that the temperature hits 32 in July. </p>
<p>Does anyone remember what the temperature equation was? I thought I still had it in my calculator.</p>
<p>does anyone remember the isoceles problem with base length 5 and the side lengths 10? what angle were they looking for? the angle corresponding to the base or the two sides? the answer was either 28.9 or 151.1… please someone let me know</p>
<p>It said acute angle so 28.1</p>
<p>scores are out</p>
<p>790 darn </p>
<p>the curve for this test must’ve been pretty awesome… lol when i finished i was just like yeah no way i got 800… i skipped like 6??? idk how that happened but i’ll take it</p>