Official October ACT Math Thread

<p>Snowolf… I don’t think so…</p>

<p>End of 5 hours is just 5 hours. </p>

<p>End of 1 hour = X3
End of 2 hours = X3^2</p>

<p>The answer should’ve been w/e X3^5 was.</p>

<p>the 5/2 question was when it asked, sin = 0.4. What is csc theta, something along those lines.</p>

<p>naw math usually has one or 0 double in the top 4 according to the “real act” test curves, so 33/32 = -4 most likley</p>

<p>zeek, they explained that earlier in the thread.</p>

<p>i don’t know the exact answer because i forgot the coordinates, saying that the original coordinates was (x,y) the new coordinates would be negative x, positive y.</p>

<p>were 5/2 and never postive x - |x| in the last ten or was it like between 41-50…anyone remember</p>

<p>was that one about the hare and the snail xy</p>

<p>Question, but the answer was 6025, right? we start off with 25 and multiply 3x every hour. at the END of the hour, because they say every hour- meaning for example,</p>

<p>5 o clock- I have 3 apples. </p>

<p>End of 5 = near 6 0 clock. therefore, we can be safe to assume that the number of apples I now have are nine.</p>

<p>What did you put?</p>

<p>slope is opposite reciprocal because the line is 90 degrees to the initial one (it said the point was rotated 90 degrees COUNTERclockwise)</p>

<p>charlie- does that go in accordance with what I said earlier?</p>

<p>the snail was xy. :D</p>

<p>Hare and snail is xy.</p>

<p>■■■ ■■■ ■■■… got the vector one, never positive (I put sometimes positive… <em>**?!), and the juice one wrong. I looked at the juice one for like 2 minutes and said </em> until I was like oh ok and got 48. -_-</p>

<p>I remember putting the 2nd largest answer… don’t remember exactly which one.</p>

<p>As long as you got it was (initial value x 3^5) you should have the right answer.</p>

<p>"naw math usually has one or 0 double in the top 4 according to the “real act” test curves, so 33/32 = -4 most likley "</p>

<p>That may be true to those tests, but there have been nicer curves lately. (You can find this by the ACT’s released practice exam they do yearly on their website, or someone a year ago posted a couple actual curves using released exams)</p>

<p>Yeah, I think the second largest was 6025. So it’s all good.</p>

<p>For the one regarding the cylinders and how much B was larger than A, it was 12, right?</p>

<p>Yes @ snowolf.</p>

<p>$19.00
the parallelagram = 64</p>

<p>t bonus= 19 for what?</p>

<p>and the parallelogram area was _4. not _5. that’s all i remember- i think it was 24, not 64 but i may be wrong.</p>

<p>ru sure that one with the snail was xy…i put xy but then changed it to x+y</p>

<p>no, it’s XY kda, because:</p>

<p>it says that the ___ (i forgot what animal it was) was x times faster than the snail. so, we have, </p>

<p>xs = Animal1</p>

<p>and then the Hare was faster by y times than the Animal1. so we now have</p>

<p>Hare = Animal1 * y</p>

<p>now, it’s asking us to determine how much faster the hare was than the snail. therefore, we have to solve for s, in terms of x and y.</p>

<p>H = sxy, plugging in A1 = sx.</p>

<p>Therefore, we can say that the Hare was xy times faster than the Snail.</p>

<p>def xy 10charsadfasdf</p>

<p>it’s xy</p>

<hr>

<p>it was xy. </p>

<p>a snail moves at his own speed.
tortise moves x times the snail. so, tortise’s speed = snail(x)
the hare moves y times as fast as the tortise. since the tortise’s speed is snail(x), the hare’s speed becomes y(snail(x), which is just xy.</p>