<p>Whoa whoa whoa! </p>
<p>V goes up, P goes down, and T stays the same? That wrong for sure. W=-PchangeinV. Volume has to decrease. Temperature has to decrease. P stays constant. </p>
<p>That’s what I got at least.</p>
<p>My test was easy. All I could do was smile at the questions that were on this.</p>
<p>I had form E if that means anything</p>
<p>i think there isnt a current on wire Y because there is no displacement.</p>
<p>my spring constant was 1280.</p>
<p>i also got 1280 for my spring constant, is that correct? sounded wrong when i got it…</p>
<p>also I got the same answers as these from an earlier page, though i had a different explanation for D</p>
<h1>1 was the fluid with the sailboat</h1>
<p>a) B/T up, Fg down
b) Buoyancy 61.25N
c) tension 428.75N
d) I put D’ > D and explained saying no longer a tension of the rope (not sure about this one)</p>
<p>also, volume goes down because work is done ON the gas. temperature goes up because heat is coming into the system. use PV=nRT to solve for pressure. pressure goes up.</p>
<p>i dont think it could be wrong</p>
<p>Whoops simple mistake. Must’ve been think about chemistry.</p>
<p>How much do they take off for wrong units? Think i put the wrong units for my spring constant</p>
<p>d’>d because the anchor is no longer pushed up by a buoyant force.</p>
<p>should be J/m^2, right?</p>
<p>yes thats exactly what i put as well for my explanation, also added that the objects mass decreases when submerged in water</p>
<p>I do believe it’s J/m^2, i put N/m. looked it up now and there seems to be multiple ways to write its units</p>
<p>units for spring constant is N/m.</p>
<p>d’> d because the anchor no longer displaces water so the buoyant force decreases; the boat sinks to make up for it.</p>
<p>the two wires one you use amperes law for magnetic field: (u)(i)/(2piR)
and then once you have that field the force is simply BIl</p>
<p>i screwed up on the current direction, but there is current in wire Y, otherwise it wouldnt feel a magnetic force</p>
<p>induced emf was just (Length of wire)(velocity)(B), i got something like .092 volts</p>
<p>for spring constant one, yes it is 1280</p>
<p>ionization energy is just going from ground state to infinite state, it was 12eV</p>
<p>for the refraction one n is just (sin angle1/sin angle2)</p>
<p>anyone know about the MC work function, interference phase changes, and standing waves?</p>
<p>@chand I’m not so sure about your explanation. It’s a rope. There’s no tension.</p>
<p>What did you use for the current for question (i) or w.e? 64A?(the current given)</p>
<p>I got a B of around .005T, i feel that might be wrong lol</p>
<p>I agree with the graph setup. But I wasn’t sure about the slope, were we suppose to pick any 2 points and get the slope? If so I took the last 2 and got an index of refraction of 1</p>
<p>.005 T sounds about right. and yeah you used the 65 amps in wire x</p>
<p>the slope i just estimated after drawing a best fit line. we didnt get the same answer; mine was about 1.4</p>
<p>ok great! that makes me feel so much better, because i really felt like i did awful
I just really hope i can get a 3</p>
<p>curve is like 115 raw score for a 5 right?</p>
<p>if you were able to get the wires one youre in pretty good shape</p>
<p>alright, u have think the anchor and the boat as a system. the mass doesnt change for both situations. however, in one of the cases, the force due to the mass is countered by a buoyant force directly up.</p>
<p>I LOVED the graph! x was the sintheta refraction and y was sintheta index therefore y over x equals index of refraction.</p>
<p>My n was like 1.2 or 1.3.</p>