<p>brandon05,
wat was the question about?</p>
<p><edit> Erased q, because there will be test-takers tomorrow too.</edit></p>
<p>It's 4/9...</p>
<p>because (5/6)(1/3) + 1/6 = 8/18 = 4/9</p>
<p>gracias.. : )</p>
<p>can someone answer my question about my raw score?</p>
<p>wat was the answer to the question about the 3 equilateral triangles where the hypothenuse was given and they asked to find the the length of the line?</p>
<p>I think it was 17, unless I'm thinking about a different question, which I easily could be.</p>
<p>idea of wat my raw score could be? i read that if u omit 20 questions and get 6 or so wrong u can still get a 600. think its true?</p>
<p>i got 17 too...</p>
<p>xoeoeix-- I think it was the last letter...25.9 or something...i worked it out and kept coming to 24.8 or soemthing, but it was the closest one?</p>
<p>For the question where the answer was 141 the question asked for the sum of a, b, and c for...</p>
<p>(3 x^3 y^2)^3=a x^b y^c</p>
<p>4/9 = 8/18</p>
<p>I left it as 8/18....we don't have to simplify on grid ins right?</p>
<p>no u dont have to.</p>
<p>No, the answer to the exponential problem wasn't 141; it was 101. BTW, JdotGreen, the first part of the sample you provided <(3 x^3 y^2)^3> doesn't look right, because the exponents were something else- unless, of course, we had different problems or something.</p>
<p>i read that u can get 600 if u omit 20 question and get 6 wrong, u think thats true?</p>
<p>How could the sum be 101? 12+12+8 or something i thought...</p>
<p>Man i'm confused.</p>
<p>oh yeah. you're right</p>
<p>Then what was the 141 problem? Oh yes, I remember it was the one where they gave you the parallel lines and 86, 133 degrees</p>
<p>Can someone describe that problem a little better for me? I'm a bit confused.</p>
<p>because the whole thing is cubed, so it's 81x^12y^8</p>
<p>jdotgreen</p>
<p>in that problem wat was the value of x</p>
<p>a=81
b=12
c=8 a+b+c=101</p>