<p>y* is defined for all positive integer values of y as the product of all positive odd factors of 3y. For example, 6<em>= 1 x 3 x 9 = 27. What is the value of 4</em>?</p>
<p>Answer: 3</p>
<p>I tried this question and i got it wrong. This question is on the Kaplan SAT Practice Test.
Can you provide an explanation for this question???</p>
<p>Thank You for your time....</p>
<p>Devansh.</p>
<p>4* 4*3=12 so we need odd factors of 12 </p>
<p>the only two are 3 & 1, so 3*1=3 tada lol</p>
<p>further explanation please? I couldn’t follow you…</p>
<p>stop being a smartass buddy. you know the answer.</p>
<p>Yes, I know they answer, but I would like to know how did they came up with the soulution. </p>
<p>IF YOU DONT KNOW THE ANSWER TO THIS QUESTION, THEN PLEASE DONT REPLY…YOU ARE JUST WASTING MY TIME…</p>
<p>from the ex. 6* = product all positive odd integers that are factors of 3y. y=6 (b/c of 6*) so find all the positive odd integers of 18 (3y = 3 x 6 = 18) and multiply them. They show 1 x 3 x 9 = 27</p>
<p>do the same for 4*</p>
<p>3y = 3 x 4 = 12</p>
<p>find all odd positive integers that are factors of 12 and multiply them
1 x 3 = 3</p>
<p>=D</p>
<p>For 6* you are looking for the positive odd factors of 18.
all the factors of 18 are 1, 2, 3, 6, 9, and 18. the odd ones are 1, 3, and 9. when you multiply those you get 27, which is the answer to 6*</p>
<p>for 4* you are looking for the positive odd factors of 12.
the factors of 12 are 1, 2, 3, 4, 6, and 12. the odd ones are 1 and 3, so the answer is 3 for 4*</p>
<p>oh, you were cereal? My bad.</p>
<p>
</p>
<p>self explanatory</p>
<p>rofl I think my first post was rather self explanatory on this topic, </p>
<p>hmm you multiply be 3 so 4(3)=12 so than you find the positive odd factors of 12, which yields 1&3 so you multiple 1(3)=3 and there’s your answer</p>
<p>1) you have to find what 3y is. In this case 3y would be 12.
2) List the factors of 12: 1, 2, 3, 4, 6, 12
3) take the odd ones: 1, 3
4) multiply them: 3
5) that’s your answer.</p>
<p>did we have to spoonfeed you?</p>
<p>Chill guys he’s asking a question on an SAT prep forum.</p>
<p>I don’t think is “extremely difficult.” There are MANY SAT questions that are more difficult than this.</p>
<p>Also, you really shouldn’t use the Kaplan SAT book for questions. Only use real questions unless you run out of real ones.</p>
<p>This question is actually rather simple once you understand it. As the problem stated, <em>y is defined as POSITIVE INTEGERS that are FACTORS of 3y. So, to determine *4, you know y=4, and 3y=3</em>4=12. The factors of 12 are as follows: 1,2,3,4,6,12. The ODD FACTORS are only 1 and 3. Finally, multiply 1 and 3 to get 3 as the correct answer.</p>
<p>Please remember that everyone has different reactions to questions. The beauty of a forum such as this one is that people who find one question to be easy should also be able to explain it with easy and understandable terms. </p>
<p>And, remember, that members LEARN the most by teaching ohers, especially when having to “spoonfeeding” someone. </p>
<p>Be patient and you will be rewarded!</p>
<p>^I did not mean that in a pretentious way as in “I thought it was easy. Why didn’t you?” It’s just that he asked for an explanation three times. I apologize if I came off harsh</p>
<p>some math questions really get to somebody and they might not understand it even if the difficulty is very low. </p>
<p>For example this geometry question is very hard but to me its easy now…</p>
<p>[Free</a> Image Hosting](<a href=“http://uploadpic.org/showpic-11621/geometry.jpg]Free”>http://uploadpic.org/showpic-11621/geometry.jpg)</p>
<p>I don’t think any CC’er can solve this question…</p>
![http://uploadpic.org/showpic-11621/geometry.jpg]Free](http://uploadpic.org/showpic-11621/geometry.jpg%5DFree){kind=link}
