<p>Page 468 in the Blue Book</p>
<p>A positive integer is said to be "tri-factorable" if it is the product of three consecutive integers. How many positive integers less than 1000 are tri-factorable?</p>
<p>Thank you :)! If there's any help that you need, I'd be happy to reciprocate.</p>
<p>123 234 345 456 567 678 789 8910 91011 =9
the next combination 10,11,12 >1000</p>
<p>Thanks 
10char</p>
<p>What about this one? Page 468 of the Blue Book. </p>
<p>It shows a stepped picture of blocks (1 block, 2 block, 3 blocks, 4 blocks).</p>
<ol>
<li>The figure above shows an arrangement of 10 squares, each with side of length k in inches. The perimeter of each figure is p inches. The area of the figure is a square inches. If p = a, what is the value of k? </li>
</ol>
<p>How would you solve this? Thanks!</p>
<p>Hey yellowd,</p>
<p>this is a tricky problem.</p>
<p>make sure to label your diagram so you can clearly see what to do.</p>
<p>they say each square has a side of “k”. Because they are SQUARES each has an area of k-squared or k^2.</p>
<p>there are 10 squares so the TOTAL area is 10k^2. Tat is equal to what they call “a”.</p>
<p>a = 10k^2</p>
<p>they also say a is equal to the perimeter “p”. How do you find perimeter?</p>
<p>The distance around!</p>
<p>So by using their measurement of k, the perimeter (and this is why labeling is important) is 16k</p>
<p>so by substituting p for a, and 16 for p the equation is:</p>
<p>16k = 10k^2</p>
<p>work through the algebra and you get k = 1.6</p>
<p>Hope that helps! Remember that this is a hard problem, and it’s MUCH MORE IMPORTANT that you are getting 1-6 and 9-15 right in this section before number 18.</p>