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<p>I think it was the Galileo one? I forgot what they paired him with, but I’m pretty sure that wasn’t him lol</p>
<p>what was the answer for the two rolling blocks attached by the string…i think it wanted the tension in the string between the 2m and 3m carts</p>
<p>There was a question about a graph, and it was like which of the following values is 0 at section A (choices: speed, acceleration, force, etc.)</p>
<p>I put none of the above?</p>
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since heat = (I^2)Rt, & the current and time should be the same, then the only thing that matters is the Resistance, so 20 ohms is half of 40 ohms?</p>
<p>That is correct for the resistance question because the current going through both resistors was the same bc there was only on Kirchoff loop</p>
<p>what was the answer for the two rolling blocks attached by the string…i think it wanted the tension in the string between the 2m and 3m carts
^did it give you the acceleration?
I’m pretty sure I put 2 for that</p>
<p>Also, I think there was another tension question, where it’s like where on a swing (or pendulum?) is the tension greatest</p>
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<p>I put net force is 0 because it was the velocity was decreasing at a constant rate, so there was no acceleration and therefore no force?</p>
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<p>I put at the lowest point of the swing</p>
<p>if velocity is decreasing at a constant rate then the acceleration is not 0…it has a negative value</p>
<p>^that’s weird though, because I’m pretty sure both accel and force were choices weren’t they?</p>
<p>and i think the graph was K.E., not velocity</p>
<p>I put at the lowest point of the swing
^I agree, but why?</p>
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yea you’re right darn i got it wrong then</p>
<p>So does that mean it was none of the above?</p>
<p>@jimbeii: Tension = mv^2/r. The velocity is the greatest at the lowest lvl.</p>
<p>^But isn’t that for uniform circular motion, not pendulums (or swing, I can’t remember)</p>
<p>^jimbeii: a pendulum is circular motion. A pendulum swing is an arc in a circle.</p>
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Speed on a stretched string = sqrt((Tension x L)/m)
Solve for tension, it is (mv^2)/L</p>
<p>So v is greatest at bottom, and therefore so is tension</p>
<p>^does that mean acceleration for a pendulum is greatest on the bottom? because f = ma, so if force of tension is greatest, acceleration is as well?</p>
<p>i put 2m for the string cart one…i remember sitting there for at least 30 seconds trying to figure it out, couldn’t, so i eventually guessed lol. was anyone confident on that one?</p>
<p>^I’m fairly confident it was 2m</p>