<p>1.) A diluted solution of HCl is prepared by adding 50.00mL of a 12 M(molarity) HCl solution to water and diluting it to 278mL; what is the molarity of the stock solution?</p>
<p>2.)If you were to mix 60.0mL of a 1.00 M(molarity) silver nitrate solution with 250ml of 0.80 M sodium chloride, what mass of silver chloride should you form?</p>
<p>Thank you</p>
<p>I don't have my calculator on me but I'll walk you through the problems.</p>
<p>1) Molarity x Volume = Molarity x Volume</p>
<p>So plugging in:</p>
<p>(12)(50) = (x)(278)</p>
<p>Solve for x.</p>
<p>2) Write an equation:</p>
<p>AgNO3 + NaCl = AgCl + NaNO3</p>
<p>Find the moles of each reactant by using:</p>
<p>Molarity: Moles/Liters</p>
<p>So for silver nitrate, you would do: .8 = x/.250 </p>
<p>Then find the limiting reagant and figure out how many moles of AgCl are formed through stoiciometry. Then convert that to grams.</p>