<p>Well, so I'm a junior in high school and right now I have a B+ (92.34 ...arghhhh!!) in my AP Calc class.</p>
<p>Since I'm so close to getting an A (less than .2 away), my teacher gave me this problem to do for extra credit and said that I could get any help I wanted (thank god, or I would never be able to do this).</p>
<p>The text for the problem is on the bottom and the diagram is the one on the right (exercise 28).</p>
<p>So I would really really really really really greatly appreciate it if one of you guys could figure this out and tell me how to do it (eg. where to draw auxilary lines, steps in proof).</p>
<p>Lol, i dont even get why I get a geometry problem for AP Calc but w/e.</p>
<p>So any help greatly appreciated! If you have any questions PM me! Please try to get this by tonight! </p>
<p>Ok. So I just looked in my old geometry book and found out the reasons for #2 and #3…but I can’t get any farther. Can you please help me out and give me more hints/explanations! Thanks!</p>
<p>Gosh, I’ve been bogged down with a ****load of stuff, bunch of papers, etc. …</p>
<p>please help me as best as you can so I can get at least one thing out of the way</p>
<p>@happysunnyshine I tried sending you another PM but it says your inbox is full… oh and one more thing that may help: the two triangles are similar.</p>
<p>let ED=x and CD=y.
Let the midpoint of AB be M. Note that MC, being the perpendicular bisector of AB, contains O, the center. Because it contains O, it is thus perpendicular to the tangent CD </p>
<p>Hence, AB is parallel to CD. This easily implies that ABF is similar to CDF.</p>
<p>By the power of a point theorem: x(x+16) = y^2
By similar triangle ratios: 2y = 10+x
Hence y =6 and x = 2.</p>
<p>you said “Let the midpoint of AB be M. Note that MC, being the perpendicular bisector of AB, contains O, the center. Because it contains O, it is thus perpendicular to the tangent CD” …how do you know that MC is the perp bisector of AB? and how do you know it contains O?</p>
<p>anybody else out there that can help me understand what hrmph1 meant when he said “Let the midpoint of AB be M. Note that MC, being the perpendicular bisector of AB, contains O, the center. Because it contains O, it is thus perpendicular to the tangent CD” …how do you know that MC is the perp bisector of AB? and how do you know it contains O?</p>