I am taking the sat the day after tomorrow and I am having a hard time with these questions.i know it is a bother but if you have the blue book and have seen this post, help me out.
1.page 417, #12
2.page 518, #17
3.page 595 #7
4.page 599 #3
5.page 600 #6
6.page 601, # 16,13
7.page 602 #25
8.page 614 #3
9.page 645#7
11.page 671#16
12.page 547 #13
13.page 544 #3
Again, it really would mean a lot. Thanks
@kunkunta I don’t have the BB so you would either have to post the questions here, or ask someone who has it.
@kunkunta No BB with me at the moment, but you can look up the explanations at http://www.collegeboard.com/html/satstudyguide/.
Some of them are not the best, but at least it’s a start.
Also - frankly, it’s a bit too much to ask for help on so many questions. Are you completely stumped on all them? How far did you get in trying to answer them?
The fact is, even after you read the solutions to all of the math questions, the chances are slim that you’ll work out your own ones to similar questions on the real test unless you invest some serious time and effort trying to crack those BB questions on your own first.
As for grammar, it takes a consistent practice to not just memorize the underlying rules, but also to be able to recognize which and when they should be applied ; cramming grammar does not give much of return.
Sorry to sound pessimistic, but it’s better for you to know your real situation than hope that some miracles will happen. Besides, you might be setting yourself up for possible freaking out on the test by jumping from question to question to question now and panicking more and more that there is so much left to learn and do.
I’ll answer a couple of them. In the future you might want to post one at a time. You’re more likely to get a faster response that way.
page 595 #7
√18 = √(9∙2) = √9 √2 = 3√2. So 18√18 = 18·3√2 = 54√2. Thus, r = 54 and t = 2. Therefore rt = 54·2 = 108, choice ©.
page 671#16
- Solution by picking a number: Using the fact that opposite sides of a rectangle are congruent, we see that 2L = 3W (there are 2 segments of length L along the left edge, and 3 segments of length W along the right edge of the large rectangle).
Let’s choose values for L and W so that 2L = 3W. The easiest such choice is L = 3 and W = 2. With these choices for L and W, the area of each small rectangle is LW = (3)(2) = 6, and the area of the large rectangular region is (12L)(10L)= (12)(3)(10)(3) = 1080.
Finally, to compute the number of small rectangles that fit inside the large rectangular region we simply divide the areas:1080/6 = 180, choice (E).
Direct solution:
The area of each small rectangle is LW, and the area of the large rectangular region is (12L)(10L).
To compute the number of small rectangles that fit inside the large rectangular region we simply divide the areas:
(12L)(10L)/LW = (120L^2)/(L(2L/3)) = 120÷2/3 = 120·3/2 = 180, choice (E).
Remark: We used the fact that 2L = 3W (see previous solution) to get that W = 2L/3.
page 547 #13
- Solution by listing:
10 + 5 + 1 + 1
10 + 1 + 1 + 1 + 1 + 1 + 1 + 1
5 + 5 + 5 + 1 + 1
5 + 5 + 1 + 1 + 1 + 1 + 1 + 1 + 1
5 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
We see that there are Six possibilities, choice (E).
@Drsteve ,thank you.I’ll write the questions down.
1.Five different points A,B,C.D and E lie on a line in that order. The length of AD is 4.5 and the length of BE is 3.5. If the length of CD is 2, what is one possible value for the length of BC?
@kunkunta draw points A, D. C is between A and D, so AC = 2.5 and CD = 2. Next, fit points B and E anywhere such that BE = 3.5 and A, B, …, E are in order (there is a range of possible answers).
@MITer94 , thanks!
2. Ignorance is not equivalent to stupidity,(for ignorance can often be correcte while stupidity cannot).
Why not (because of it’s correctible nature)?
@kunkunta Use “its.”
Ignorance is not equivalent to stupidity, because of its correctable nature.
This sentence is ambiguous, and hence, incorrect. What does “its” refer to?
@MITer94 , got it!
3. Intense preoccupation (on) technique (appears to be) the one trait that great pianists (have in) common.
- When it is noon eastern standard time (EST) in new york city, it is 9:00 A.M. Pacific standard time (PST) in san francisco. A plane took off from new york city at noon EST and arrived in san francisco at 4:00 P.M. on the same day. If the second plane left san francisco at noon PST and took exactly the same amount of time for the trip, what was the plane's arrival time (EST) in new york city?
- If a, b, c, and f are four nonzero numbers, then all of the following proportions are equivalent EXCEPT a, a/f=b/c b, f/c=b/a c, c/a=f/b d, a/c=b/f e,af/bc=1/1
@kunkunta 4. Ah yes, time zones. It did not simply take 4 hours to get from NYC to SFO. You have to add 3 hours for the time difference (i.e. the plane leaves at 12:00 EST, and arrives 4:00 PST or 7:00 EST), so the flight took 7 hours.
A flight leaving SFO at 12:00 PM would take 7 hours, then add the 3 hours to account for the time difference --> 10:00 PM.
- Easiest to get rid of the annoying fractions by cross-multiplying everything: A) ac = bf B) af = bc C) af = bc D) af = bc E) af = bc
From here the answer is definitely A.
@ MITer94 ,any clues about question #3 ?
6. If a and b are positive integers and [a^(1/2)b^(1/3)]^6=438, what is the value of ab?
@kunkunta my gut tells me it should be “preoccupation with…” Maybe ask someone else to confirm.
- Use the rules of exponents! Finding ways to simplify the problem should always be your goal on these problems.
@MITer94 , I applied every rule I could possibly think of. May be a hint?
@kunkunta Actually nvm what I just said - assuming you typed the problem correctly, the problem appears unsolvable. But you should still try to simplify every problem! 
We have a^3 * b^2 = 438 where a and b are positive integers. This should clue “factorization.” But 438 = 2373, so we cannot choose such a and b. Did you type the question correctly?
@MITer94 , I think you didn’t notice the “^6” next to the bracket that encompasses the variables.
@MITer94 , you didn’t “^6”.