<p>Has anyone used the guide? If so, how is it?</p>
<p>In any case, I have a couple of math questions from pwnthesat.com:</p>
<p>Can someone please explain #5, 11, and 14 to me? </p>
<p>For #5, I keep getting -26, but that's not the correct answer. </p>
<p>For #11 and 14, I''m clueless.</p>
<p>For #11 - C - lets just say (m+n)=3. So q=4^3</p>
<p>So if 2(m+n)=6. then X=4^6</p>
<p>(4^3)^2 = 4^6</p>
<p>so the answer is q^2</p>
<p>For #14 - B</p>
<p>I. - NO - term 2 is 4 (4^2 = 16)
II. - Yes - 2^0 = 1, 2^2=4, 2^4=16 etc…
III. - NO - Plug in the equation for n = 53,you get 2^104 - which is way more than 6 digits</p>
<p>For #5 the answer is C</p>
<p>Just assume this (-23,-23,0,0,010)</p>
<p>-36/6 = -6</p>
<p>There is an easier way to do 5 than trying to guess numbers that work.</p>
<hr>
<p>A) (a + b + c + d + e + f)/6 = -6 Given</p>
<p>B) a+b+c+d = 10 Given</p>
<p>(10 + e + f)/6 = -6 Substitute B into A</p>
<p>10 + e + f = -36 Multiply 6 by both sides</p>
<p>e + f = -46 Subtract 10 from both sides</p>
<p>e + f = -46 so (e + f)/2 = -23</p>
<p>So the answer is C) -23</p>
<p>^Kieran, 14 is D. III works as well because it’s asking if the UNITS digits of the 53rd term is 6, not if it has 6 digits</p>
<p>^ Oops my bad</p>
<p>Wow @Braniac</p>
<p>How could I have not noticed that :(</p>
<ol>
<li>Substitute</li>
</ol>
<p>4^3 = Q</p>
<p>Q = 64</p>
<p>4^6 = 4096</p>
<p>Sqr Root of 4096 = 64 = Q^2</p>
<p>Brainic is right but here different way to solve number 5.</p>
<p>5)</p>
<p>Since 4 number have have sum of 10 then 10 + x + y / 6 = -6;</p>
<p>10 + x + y = -36;
x + y = -23;</p>
<p>14) You just can substitute numbers 1,4,16,64;</p>
<p>First one is saying nth term in pattern is equal to 4^n
it should be 4^n-1; For example second term is 4^1,etc;</p>
<p>Second nth term n pattern is equal to 2^2(n-1)</p>
<p>lets say n - 1 = 2</p>
<p>2^2(2-1) = 2^2 = 4,so this is right.</p>
<p>the unit digit of 53rd term is 6.
We can see the pattern of 4^n and see if it repeats certain pattern</p>
<p>4,16,64,256,1024,4096,16384</p>
<p>4,16,
64,256,
1024,4096,
16384,65536</p>
<p>Notice pattern is
4,6
4,6
4,6
4,6
So it repeats every 2 terms then
53 / 2 = 26.5 Ignore the decimal we have 26 * 2 = 52,but since we know we have 1 term more which is 1,so 52 is actually the starting of the sequence,so 53 have the term 6 in it.</p>
<p>So its choice D;</p>
<p>I hope that makes sense.</p>
<p>Thank you all for the help :). I understand all the problems now :D.</p>
<p>For number one,
Am I the only one getting 35 instead of 44?
=(16x-18)+5
=(16(3)-18)+5
=34</p>
<p>
</p>
<p>
</p>
<p>g(x) = f(2x) + 5
g(3) = f(2 * 3) + 5
g(3) = f(6) + 5</p>
<p>f(x) = 8x – 9
f(6) = 8(6) – 9
f(6) = 39</p>
<p>g(3) = f(6) + 5
g(3) = 39 + 5
g(3) = 44</p>
<p>Can someone explain number 20 to me? It is the only one I do not understand.</p>
<p>
</p>
<p>
</p>
<p>From the question, you can deduce that s is greater or equal to 39 and less than or equal to 75.</p>
<p>39 ≤ s ≤ 75</p>
<p>Which of the answer choices simplify to the above inequality? Well, for each absolute value inequality, there are two normal inequalities. Find the easier of the two normal inequalities by simply taking off the absolute value. By doing so, I can quickly calculate that neither (A), (B), (C), nor (D) total up to 39 or 75. (Do you get what I’m doing here? I can elaborate more if needed.)</p>
<p>That leaves (E). You can check the answer if you would like.
|s – 57| ≤ 18
s – 57 ≤ 18 so s ≤ 75
s - 57 ≥ -18 so s ≥ 39</p>
<p>39 ≤ s ≤ 75</p>
<p>That makes sense now. Thanks!</p>
<p>no problem</p>
<p>I’m happy to help :)</p>