<p>Hey, could anyone explain today's question of the day (may 30) because I'm not really understanding collegeboard's explanation. Thanks a bunch.</p>
<p>All you need to do is get the original formula (a+b)/(b+c) into terms of one variable. This is possible because the additional information gives you fractions (a/b and b/c I think… I’m not looking at it right now). It’s easiest to solve in terms of b, so solve each fraction (a=#b);(c=#b) where #=some number.</p>
<p>Then just plug into the original formula and you figured out b. Then just simple algebra from there.</p>