<p>hey i have a quick question for you calculus people:</p>
<p>if g(x) = 1 / f(x), then what does g'(x) = ?</p>
<p>i tried using the quotient rule and got f'(x) / f(x)^2, but i doubt that's right for some reason. i know there's some sort of other answer.</p>
<p>thanks!</p>
<p>I think you could change it to g(X) = 1*f(X)^(-1), so g'(X) would equal -f(x)^-2 using the multiplication rule</p>
<p>If you use the quotient rule, you should get -f'(x) / f(x)^2. = -f(x)^-2 * f'(x)</p>
<p>This is the same result as you get if you use the power rule properly. Remember that since f(x) is a function, you need to use the chain rule. Therefore, using the power rule, the derivitive of f(x)^-1 is -f(x)^-2 * f'(x)</p>
<p>you're awesome! tanman!</p>