quick math question !!

Test Preparation SAT Preparation
1

<p>A list consists of different integers. If a number is to be chosen at random from the list, the probability that the number chosen will be odd is 1/3. What is the probability that the number chosen will be even?</p>

<p>I think that this problem can be interpreted in two different ways.
The answer is 2/3, however, I disagree to an extent.</p>

<p>I got 1/3 because I used the list 0,1,2 as an example.
It follows the rules of the problem, and since 0 is neither positive nor negative, I chose the answer to be 1/3. When they say that the answer is 2/3, how can they be sure that a 0 is not included in the set? This is from a previously administered test too. Someone explain?</p>

2

<p>0 is an even number because even numbers = 2k where k is any integer.</p>

3

<p>thanks
10char</p>

4

<p>Actually, you don’t need to plug in numbers!! You know that 0 is an even number so all the numbers that are not odd are even. Therefore, if 1/3 of the numbers are odd, 2/3 are even!!</p>