Real SAT math problems

Test Preparation SAT Preparation
1

<p>Hi guys I got these 3 wrong in real SAT math.</p>

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It has image so see up.</p>

<p>8)Based on the portions of the graphs of the functions f and g shown above, what are all values of x between -6 and 6 for which g(x) > f(x).</p>

<p>Sales of Book B; Total number of Copies Sold</p>

<p>End of 1st week 3200
End of 2nd week 5500
End of 3rd week 6800
End of 4th week 7400
end of 5th week 7700</p>

<p>11)The table above shows the total number of copies of Book B that were sold by the end of each of the first 5 week of its publication. How many copies of the book were sold during the 3rd week of its publication?</p>

<p>I don't rlly understand this question shouldn't the third week be just 6800 ?? Since thats how much book were sold !!? I didn't really sleep yesterday so I am sure I am missing something here and it would end being some stupid error :D.</p>

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<p>14)Point O is the center of both circles in the figure above. If the circumference of the large circle is 36 and the radius of the small circle is half of the radius of the large circle, what is the length of the darkened arc?</p>

<p>A)10
B)8
C)6
D)4
E)2</p>

<p>The answer is E,but why I solved it like this !!</p>

<p>RBigCircle = 36/2 = 18;
RSmallCIrcle = 18/2 = 9;</p>

<p>Circumference of big circle = 9 * 2 = 18;</p>

<p>the darkened should be 80/360 * 18 = 2/9 * 18 = 4,but the answer is E how is it 2 !??</p>

<p>Answers are:
8)B
11)1300
14)E</p>

<p>Thanks guys in advance and good luck to all who will do the October test.</p>

2

<p>8) B
11) the number of books sold during week3 is 6800-5500=1300</p>

3

<p>sorry I didn’t explain 8)
It is pretty clear from the graph: when graph of g(x) is “above” graph of f(x), then g(x) is higher tahn f(x). On points x=-3 and x=0 f=g so, these points do not satisfy the condition g(x)>f(x). You are left with the interval -3<x<0</p>

4

<p>you need to find the radius of small circle
The large circle radius, LR, is such as: 2<em>PI</em>LR=36
thus, LR=36/(2<em>PI)=18/PI
The small circle radius, being half of this, SR=18/(2</em>PI)
The circumference of the small circle is 2<em>PI</em>18/(2<em>PI)=18
The length of the arc is as per your calculation: 18</em>80/360=4
Are you sure E is the correct answer?</p>

5

<p>E is not the answer. It is D.</p>

6

<p>Yes, you guys are right I doubled checked the answer is D not E I didn’t see it correctly.
I guess I got that question right after all.</p>

<p>Thanks alot farfalla for help it makes perfect sense.</p>

7

<p>I don’t understand this for problem number 8 why is it less than 0 ??
I see how its bigger than -3 but why < 0 it goes forever bigger than f(x).</p>

8

<p>for x>0, f(x) which is the straight line is “above” g(x) thus g(x) is less than f(x)</p>

9

<p>Yes I see noow I got them mixed I see its logic now.
Thanks</p>