Ok… This is the whole question
There is the same number of boys and girls on a school bus when it departs from school. At the first stop, 4 boys get off the bus and nobody gets on. After the first stop, there are twice as many girls as boys on the bus. How many girls are on the bus
a. 4
b. 6
c. 8
d. 12
e. 16
The answer is 8.
I do know how to set up the equation and solve the problem. Putting x as boys and y as girls the equation would be:
x = y (since is the same number of boys and girls on a school bus when it departs)
Then I face a problem!
I set up equation as x-4 = 2y, but to get the right answer, I would need to put 2(x-4) = y.
It seems to me that I am interpreting this part of the problem --> “there are twice as many girls as boys on the bus” wrong. I would set up equation as x = 2y because for every boy there are 2 girls. Can someone point out the flaw for x = 2y?
And more I think about it I get confused. Please math gurus, help me!