SAT II Chem question

<p>If you titrate 1 M of H2SO4 solution against 50 mL of 1 M NaOH solution, what volume of H2SO4, in mL, will be needed for neutralization?</p>

<p>I thought the answer was 50, but it's actually 25.</p>

<p>The explanation says that the formula to be used is: MaVa = 1/2(MbVb)</p>

<p>Where does the 1/2 come from? Please explain!!</p>

<p>H2SO4 is a strong diprotic acid. For every molecule of it there’s 2 H+ molecules, so it’ll only take half as much volume to titrate a strong monoprotic base.</p>

<p>use the formula i<em>Ma</em>Va = i<em>Mb</em>Vb. I is the van hoff factor and would be the number of Hs or OHs. so its 2<em>1</em>x = 1<em>50</em>1 and now when you solve for x you get 25. Note that there are 2 Hs in sulfuric acid and only 1 OH in Sodium Hydroxide.</p>