<p>i actually believe the area of the semicircle was 17/2pi- i was sure of it on the test day...dont really remember the problem right now...hope im not wrong</p>
<p>can anyone restate question number 49?<br>
it was the one with like some function that equals one</p>
<p>i put the answer as 7, but others said 2</p>
<p>anyone confirm right answer?</p>
<p>im 99.99999% sure 49 was 7. Check the explanation a few posts previous to this.</p>
<p>i think what people did who got 2 as the answer just set what the final equation was (4x-7) equal to 1, but the problem said f(2x+3)=4x-7, making x when f(x)=1 to be 7.</p>
<p>khrisha... you sure? i did the problem like 3 times on test day and kept geting 17/4pi... maybe you found the area of the whole circle as 17/2pi and forgot to divide by 2 for the semicircle? i dont know, i just thought i was pretty confident with 17/4... can anyone else confirm?</p>
<p>yep. igot 17pi / 4</p>
<p>I'm pretty sure the question was this (for the 17pi/4)</p>
<p>A semi-circle w/ unknown diameter. There were 2 lines reaching to a point on the left, of length 3 and 5. You use pythagorean; diameter = sqr34. Do the math from there--divide by two for radius, square and *pi, divide by two because it's a semi.</p>
<p>vcv, whatd you get for 49?</p>
<p>there are a lot of different answers...</p>
<p>I didn't do 49. The last 3 I didn't wanna risk the time/chance of getting wrong and just skipped to go back and do others.</p>
<p>9 blank none wrong.. where does that leave me.. any chance of getting a 700?.. ugh why did i leave so many.. ::sigh::</p>
<p>can anyone post up other difficult problems he/she encountered?
i seem to have forgotten most of the problems for some reason..</p>
<p>and also, assuming for 49, 7 is the correct answer, i think i only got 1 wrong
should i cancel?<br>
i heard that if you dont get an 800, youre already in the low 90% percentile</p>
<p>
[quote]
i heard that if you dont get an 800, youre already in the low 90% percentile
[/quote]
</p>
<p>I think thats b****x cuz my fren got a 750 and was 95% percntile.</p>
<p><strong><em>- i forgot to divide by 2 at the end for the semi-</em></strong>!!!!
that makes 2 wrong (the subcommittee problem) and 1 skipped</p>
<p>yes that was it. 17/4pi</p>
<p>are you guys sure that 7 is the right answer for 49??? i hope so!</p>
<p>the question was:</p>
<p>f(2x+3) = 4x-7, what t makes f(t) = 1?</p>
<p>how did you get that?</p>
<p>ive been debating about question 49 between answers 2 and 7
im almost 90% sure its 7...i kinda forgot how i did it though..lol</p>
<p>can someone please tell me exactly what the question was for 17pi/4?? really need to know!</p>
<p>callthecops-- I posted the question on page 3.</p>
<p>CALLTHECOPS:</p>
<p>NUMBER 49 (PUTTING IN CAPS B/C ITS BEEN POSTED TWICE ALREADY):</p>
<p>it said f(2x+3)=4x-7, by inspection one may figure out the original function to be f(x)=2x-13;
set this equal to 1 because they ask for value of x is f(t)=1
1=2x-13
2x=14
x=7</p>
<p>i mean what value of t**... argh stupid variables</p>
<p>sorry, how do you know that the original funtion is f(x)=2x-13? that's the step I don't understand</p>