<p>@RandomHSer Sorry I might sound stupid but i get that g(x)=x(x-1). the second part I still don’t really see :(</p>
<p>Typo in my above post: g(m) should read g(m+2). Put in m+2 for x in the expression you wrote for g(x).</p>
<p>@RandomHSer I’m sorry but I still don’t see how you get that. I know 2 works for m because 2+2(3)=12 I get the algebraic part. just don’t see how and what you substitute</p>
<p>@sat2014</p>
<p>If g(x)=x(x-1), then g(m+2)=(m+2)(m+2-1), right? Set this equal to 12.</p>
<p>@RandomHSer you lose me at how g(m+2)=(m+2)(m+2-1) don’t know how you got that</p>
<p>@ sat2014 If you replace every ‘x’ you see in x(x-1) with a ‘m+2’, what do you get?</p>
<p>@RandomHSer I finally get it! thanks for not giving up on me 
it takes me a WHILE to get SAT math.</p>
<p>Ok, good job and good luck on the real test!</p>
<p><a href=“Box”>https://app.box.com/s/e86elz1s58pj6gbtlqmq</a> Hi, If anybody could help me with section 3 I’d appreciate it. Got 15/18 Correct. # 13 I got correct but I kind of guessed. I want to know exactly how to get it. 14 I had no idea how to do. 15 I tried so many ways to do it but failed 
and 17 I got wrong. 13 14 15 and 17 I need help with. Thanks!</p>
<p><a href=“Box”>https://app.box.com/s/e86elz1s58pj6gbtlqmq</a> For section 4 I need help with 18 and 20 please. 14 i didn’t use all the answer choices which is why I got it wrong and for 18 how is the answer not D? 1/2 times a 1/2 times a 1/2 is .125. .125 times 8 = 1. 20 I nibbled away at it but couldn’t finish it. please help if you can. thanks.</p>
<p>@sat2014
Sec. 3</p>
<ol>
<li><p>Just draw it and pick the other endpoint at (5,0). Ans is 8.</p></li>
<li><p>The naive solution is 500/5 = 100. However, fence posts are at the first and last posts so we need to add 1 for inclusivity. The answer is 101.</p></li>
<li><p>The quadratic is symmetric about the line x = 3.5 (we know this because (0,10) and (7,10) are on the quadratic). So 3.5 must be halfway between -1.5 and t, so t = 8.</p></li>
<li><p>We want to be greedy here. If we buy 13 or more machines at $1200 each, then the median is $1200 which doesn’t work (list it out and you’ll see). However if we buy 11 machines at $1200 each, it works. Since x is odd, 11 is the maximum.</p></li>
</ol>
<p>Sec. 4</p>
<ol>
<li><p>Rearranging and subtracting y from both sides gives 2x < 0 <–> x < 0, so the answer is D.</p></li>
<li><p>Surface area, not volume. Surface area of large cube is 6 in^2, and surface area of eight smaller cubes is 8<em>6</em>(1/2 in)^2 = 12 in^2. Surface area increased by 6 in^2, C.</p></li>
<li><p>Denote the radius of the inner circle by r. Draw an isosceles triangle connecting the center of the square, and the centers of two adjacent circles. It turns out that the triangle is a right triangle by symmetry. The side lengths of this isosceles triangle are 1+r, 1+r, and hypotenuse 2. Using 45-45-90 triangles, 1+r = sqrt(2), so r = sqrt(2) - 1, D.</p></li>
</ol>
<p>@MITer94 Thanks, need help with problems 5 9 and 14. got 16 wrong because forgot 0 was an integer! 9 I guessed and got it but I still want to know exactly how to do it. <a href=“Box”>https://app.box.com/s/e86elz1s58pj6gbtlqmq</a></p>
<p>@MITer94 Section 8</p>
<p>@MITer94 for number 15. How is t 8? how do you know? I see 3.5 is in the middle but how do you get 8?</p>
<ol>
<li>Several ways to arrive at the solution, but notice that (1,1) and (6,6) are on the square (AB has slope -1, the sides are parallel to the axes). A</li>
</ol>
<p>9.The width of the rectangle is 6, so the area of the rectangle is 10*6 = 60. Just subtract off the unshaded area, which forms a full circle of radius 3 in this case. The shaded area is 60 - 9pi.E</p>
<ol>
<li><p>This one is simple even though it looks confusing at first. Basically, if you add one more pail, the height increases by c, which is 2 in this case. This is the definition of slope. C</p></li>
<li><p>0 is indeed an integer.</p></li>
</ol>
<p>For 15, 3.5 is halfway between -1.5 and t, because of symmetry. Since you subtract 4.5 to get to -1.5, you can add 4.5 to get to 8.</p>
<p>Btw, #10 on section 8 is one of the few questions I’ve ever seen where the answer is “It cannot be determined from the information given.”</p>
<p>@MITer94 Thanks! got a 670 on the Math. Test was considered “medium” for math. Personally, what do you prefer when it comes to the difficulty for the math section? I honestly prefer an easy test with a harsh curve or a medium test. I tend to struggle with a hard math SAT</p>
<p>@MITer94 for 15 there is a problem. if you subtract 4.5 from 3.5 you get -1, not -1.5. So I don’t think that works</p>
<p>Whoops, I wasn’t thinking through. The quadratic is symmetric about x = 3.5, so t would be 8.5, not 8. Thanks for pointing that out.</p>
<p>As to your previous question, I’m not sure. I did a lot of math contests so the SAT math came by as very easy for me. I’d most likely fail on a tricky SAT, one with easy questions but lots of places where it’s easy to make a dumb error.</p>
<p>Hi, new here, could someone help me with this problem please?</p>
<p>The cost of a telephone call using long distance carrier A is $1.00 for any time up to and including 20 mins and $0.07 per minute thereafter. The cost of carrier B is $0.06 per min for any amount of time. For a call that lasts ‘t’ mins, the cost using carrier A is the same as the cost using carrier B. If ‘t’ is a positive integer greater than 20, what is the value of ‘t’?</p>
<p>I think I found a way but it’s confusing and long, is there a simple method?</p>
<p>Just set up an equation:</p>
<p>1.00 + .07(t-20) = .06t</p>
<p>t = 40</p>