SAT Math problems

Test Preparation SAT Preparation
1

<p>i seriously need help in math as i dont understand these questions ( i am getting a 600 in math as of now wow :( )</p>

<p>Please can someone teach the idiot (me) how to do these SAT questions</p>

<hr>

<p>If 299 is divisible by 2B, and B represents a positive digit, what is the value of B?</p>

<p>A) 2
B) 3
C) 4
D) 6
E) 9</p>

<p>The answer is B but i dont understand why? 2(3) = 6 ...299/6 is not divisible by 6 evenly</p>

<h2> idk can someone help</h2>

<p>Given a sequence of integers where every third term is a multiple of 3 and every second term is a multiple of 2, which of the following could be the value of the 144th term in the sequence?</p>

<p>A) 15
B) 44
C) 81
D) 114
E) 206</p>

<p>How do you do these types of problems? The answer is D btw.</p>

<p>Is there some sort of formula? I divided 144 by 3 and got an even number, so that means the 144th term is divisible by 3? And in that case 81, 114, and 15 are divisible by 3</p>

<hr>

<p>Trey cycles to eactly one of three possible destinations every morning before school. There are two routes to each of Destinations A and B. There is only one route to Destination C. There are 2 return routes from from Destination A, 4 return routes from Destination B, and 3 return routes from Destination C. How many different round trips can Trey choose for his morning ride?</p>

<p>A) 9
B) 14
C) 15
D) 24
E) 96</p>

<p>The answer is C.</p>

<p>How do i even approach this problem? Any tips / walk through?</p>

<hr>

<p>If the ratio of a to b is 2 to 5, and the ratio of b to c is 1 to 4, what is the ratio of a to c?</p>

<p>A) 1:2
B) 1:10
C) 5:8
D) 5:4
E) 5:2</p>

<p>The answer is B. I put A as i thought 2:4 (a to c) is reduced to 1:2?</p>

<p>Why was this B not A?</p>

<p>ETS got me</p>

<hr>

<p>Both C and D are positive numbers . If X - D 5
----- = ---
CX 2</p>

<p>what is the value of x in terms of c and d?</p>

<p>A) 10 (5 - d) + c
B)10(5 + d) - c
C) 5cd</p>

<p>D)
2d
(-) ----- ( its a negative fraction)
5c -2</p>

<p>E) 2d
------
5c - 2</p>

<p>The answer is D.</p>

<p>I put E as a guess but after i cross multiplied and simplified i keep getting X = 2d/ 2- 5c</p>

<hr>

<p>THANK YOU EVERYONE FOR READING THIS FAR AND ACTUALLY TRYING TO HELP ME.</p>

<p>This is why i love you guys . Props .</p>

2

<p>for the first one, they mean 23, not 2 x 3. 299/23 = 13</p>

3

<p>Oh wow thanks for the response...ahhh tricky , so used to seeing that as multiplying situation</p>

4

<p>You would multiply it if the letter were lower case and italicised. (2*b* instead of 2B).</p>

5

<p>Ah thanks for the tip!</p>

<p>aNYONE else know the answers to the other question?</p>

6

<p>the cycles one is a basic probability one. It's the same as, i have 3 shirts, 3 pants, 3 hats, how many combinations of clothes can i wear? Multiply the numbers, and u get 24.</p>

<p>The ratio one is quite simple too. Just multiply it so B is = 5. So the ratio of b and c is 5/20. Replace 5 with 2, and it becomes 2/20, or 1/10.</p>

7

<p>If the ratio of a to b is 2 to 5, and the ratio of b to c is 1 to 4, what is the ratio of a to c?</p>

<p>A) 1:2
B) 1:10
C) 5:8
D) 5:4
E) 5:2</p>

<p>The answer is B. I put A as i thought 2:4 (a to c) is reduced to 1:2?</p>

<p>Why was this B not A?</p>

<p>a : b
2 : 5</p>

<p>b : c
1 : 4</p>

<p>but, since you know from the previous ratio that b=5, you can say:</p>

<p>b : c
5 : 20 (multiply both sides by 5)</p>

<p>a : c
2 : 20 (from first ratio and the previous one)</p>

<p>that reduces to:</p>

<p>a : c
1 : 10</p>

<p>EDIT:</p>

<p>Sorry, I didn't see your question.</p>

<p>The reason you can't say 2:4 is because the value for b in those two ratios aren't the same. In one, b = 5, and in the other, b = 1. That's why I multiplied the ratio that said 1:4 by 5 - to make b in the second one also equal 5.</p>

<p>Hope that helps.</p>

8

<p>Given a sequence of integers where every third term is a multiple of 3 and every second term is a multiple of 2, which of the following could be the value of the 144th term in the sequence?</p>

<p>A) 15
B) 44
C) 81
D) 114
E) 206</p>

<p>144th term should be both divisible by 2 and 3. thus it's a mutiple of 6. only 114 is a mutiple of 6</p>

9

<p>Trey cycles to eactly one of three possible destinations every morning before school. There are two routes to each of Destinations A and B. There is only one route to Destination C. There are 2 return routes from from Destination A, 4 return routes from Destination B, and 3 return routes from Destination C. How many different round trips can Trey choose for his morning ride?</p>

<p>A) 9
B) 14
C) 15
D) 24
E) 96</p>

<p>you know if we have x ways to arrive one place and y ways to leave there, we have x<em>y ways in total. right? so for A, there are 2</em>2=4 ways, for B there are 2<em>4=8 ways, for C there are 1</em>3=3 ways. thus we have 4+8+3=15 ways in total.</p>

10

<p>If the ratio of a to b is 2 to 5, and the ratio of b to c is 1 to 4, what is the ratio of a to c?</p>

<p>A) 1:2
B) 1:10
C) 5:8
D) 5:4
E) 5:2</p>

<p>hey lets put some specific numbers. a:b=2:5, lets assume a=2 and b=5. b:c=1:4, and b=5, so c=20. thus a:c=2:20=1:10</p>

11

<p>well...i think the last question is not so clear....could you repost it? can't figure out the question..</p>

12

<p>from which book did u get these questions from?</p>